Question

Suppose an image is represented on a display screen by a square array containing 256 columns and 256 rows of pixels. If for each pixel, 3 bytes are required to encode the color and 8 bytes to encode the intensity, how many byte-size memory cells are required to hold the entire picture?

Answer 1

Solution and Explanation:

Given data: number of rows = 256, number of columns = 256, number of bytes that are required for each pixel to encode the color = 3, number of bytes that are required to encode the intensity = 8

calculation of vyte size memory cells is as follows:

the number of pixels = number of rows mulitply with number of columns

= 256 mulitply with 256 = 65536

each pixel require 8 bit, therefore, each pixel require 1 byte

the size of memory must be 65536 bytes.

This is 65536 divide 1024 = 64KB