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3 years ago

14 - 2xy when x = -6 and y = 2.

Mathematics

2 answers:

alex41 [277]3 years ago

8 0

Answer:38

Step-by-step explanation:

Variables come first. So you plug in -6 and 2, the new expression would be

14 - 2(-6)(2). Then you do the multiplication, so 2(-6)(2) becomes -24,

14 - (-24) is 38.

Paraphin [41]3 years ago

3 0

Answer:

$38$

Step-by-step explanation:

14 - 2xy when x = -6 and y = 2.

$14 - 2( - 6)(2) \\ 14 - 2 \times ( - 12) \\ 14 + 24 = 38$

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Y=2x+3 using function equation

RoseWind [281]

Slope: 2
Y-intercept: -3

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3 years ago

A grocery store bought some mangoes at a rate of 5 for a dollar. They were separated into two stacks, one of which was sold at a

Alexus [3.1K]

Answer:

The ratio of the number of mangoes in the $3 stack to those in the $6 stack is 1 : 2

Step-by-step explanation:

Let the number of mangoes bought by the grocery store be n. Also let the number of mango sold for $3 in one stack be x and the number of mango sold for $6 in the second stack be y.

Therefore:

x + y = z (1)

Also, the mangoes was sold at break even price, that is the cost of the mango and the price it was sold for was the same. Therefore:

Cost of buying = Price it was sold for

The cost of the mango = 5z and the price it was sold for = 3x + 6y

3x + 6y = 5z (2)

Substituting z = x + y in equation 1

3x + 6y = 5(x + y)

3x + 6y = 5x + 5y

6y - 5y = 5x - 3x

y = 2x

x / y = 1/ 2 = 1 : 2

The ratio of the number of mangoes in the $3 stack to those in the $6 stack is 1 : 2

8 0

3 years ago

Find the area of each parallelogram. What is the relationship between the areas?

castortr0y [4]

Answer:

Area of parallelogram is given by:

$A = bh$

where b is the base and h is the height of parallelogram.

In parallelogram TQRS.

Coordinate of TQRS are;

T(8, 16), Q(4, 4), R(16, 4) and S(20, 16)

Coordinate of T'Q'R'S' are;

T'(2, 4), Q'(1, 1), R'(4, 1) and S'(5, 4)

Find the length of QR and PT:

Using distance(D) formula:

$D = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$QR = \sqrt{(4-16)^2+(4-4)^2} =\sqrt{(-12)^2+0}= \sqrt{144}= 12$ units

Similarly;

For PT:

From the graph:

P(8, 4) and T(8, 16), then

$PT = \sqrt{(8-8)^2+(4-16)^2} =\sqrt{(-0)^2+(-12)^2}= \sqrt{144}= 12$ units

In parallelogram TQRS

PT represents the height and QR represents the base of the parallelogram respectively.

then;

Area of parallelogram TQRS = $QR \cdot PT$

⇒Area of parallelogram TQRS = $12 \cdot 12 = 144$ unit square.

Now, in parallelogram T'Q'R'S'

Q'R' represents the base and P'T' represents the height of the parallelogram respectively.

here, P'(2, 1)

Find the length of Q'R' and P'T':

$Q'R' = \sqrt{(1-4)^2+(1-1)^2} =\sqrt{(-3)^2+0}= \sqrt{9}= 3$ units

$P'T' = \sqrt{(2-2)^2+(1-4)^2} =\sqrt{(-0)^2+(-3)^2}= \sqrt{9}= 3$ units

Then;

Area of parallelogram T'Q'R'S' = $Q'R' \cdot P'T'$

Area of parallelogram T'Q'R'S' = $9 \cdot 9= 81$ unit square.

Now, we have to find the relationship between the areas.

$\frac{\text{Area of parallelogram TQRS}}{\text{Area of parallelogram T'Q'R'S'}} = \frac{144}{81}$

then;

the relationship between the areas of TQRS and T'Q'R'S' is:

$\text{Area of parallelogram TQRS} = \frac{144}{81} \cdot {\text{Area of parallelogram T'Q'R'S'}$

7 0

3 years ago

Chad ran a red light and hit another car. He decided to file a claim for damage

pochemuha

Answer:

Comprehensive deductible

Step-by-step explanation:

There is nothing called Premium deductible rather deductible determines how higher of lower a premium on a subject matter of insurance can be. Deductible is the amount with the insured have to bear at loss and any excess above the loss will be compensated by the insurance company.

Comprehensive deductible is the application to only to comprehensive insurance which was what Chad had on his motor vehicle. Comprehensive insurance covers majority of peril that happens to the insured vehicle. Therefore, comprehensive deductible is the deductible Chad has to bear himself before the insurance company take other losses upon theirself..

If he had $500 deductible on his car and total repair cost $700, then he will bear the $500 while the insurance company is entitled to pay only $200 as per policy statement.

6 0

3 years ago

Read 2 more answers

Paul Kim estimates that he will drive about 10,000 miles during the year and will have $3,460 in annual fixed costs. He projects

Mama L [17]

Answer:

The maximum annual variable cost he can have to reach his projection is $1,940

Step-by-step explanation:

Given;

Number of miles drive per year N = 10,000 miles

Total annual Fixed cost F = $3,460

cost per mile(rate) r = $0.54 or less

Total cost = fixed cost + variable cost

Total cost = cost per mile × number of miles

Total cost = r × N = $0.54 × 10,000 = $5,400

Let V represent the total variable cost per year;

F + V ≤ r × N

Substituting the values;

3,460 + V ≤ 5,400

V ≤ 5,400 - 3,460

V ≤ 1,940

The maximum annual variable cost he can have to reach his projection is $1,940

5 0

3 years ago