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Brrunno [24]
3 years ago
9

If 3,x,y,18 are in arithmetric progression , find the value of x and y

Mathematics
1 answer:
Ksivusya [100]3 years ago
6 0
Given:
arithmetic progression
a₁ = 3
a₂ = x
a₃ = y
a₄ = 18

Solution:
The arithmetic progression has general formula to determine nth term
a₁ + d(n - 1) = an
a₁ represents first term, d represents difference, n represents number of terms, an represents nth term

First we should find out the value of d, by submitting a₄ to the formula
a₁ + d(n - 1) = an
a₁ + d(4 - 1) = a₄
3 + d(3) = 18
3 + 3d = 18
3d = 15
d = 5
The difference of the sequence is 5

Second, determine x and y
x = a₂
x = a₁ + d(2 - 1)
x = 3 + 5(1)
x = 8

y = a₃
y = a₁ + d(3 - 1)
y = 3 + 5(2)
y = 13

The value of x is 8, the value of y is 13
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What is the answer?​
Mrrafil [7]

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53°

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The angle that measures 143 is vertical to the right angle and the ? angle.

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6 0
3 years ago
Determine a área total e perímetro da figura a seguir:<br><br> Apresente os cálculos.
ra1l [238]

Answer:

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6 0
2 years ago
The population of rabbits on an island is growing exponentially. In the year 1994, the population of rabbits was 9600, and by 20
drek231 [11]

Answer:

49243

Step-by-step explanation:

Given that the population of rabbits on an island is growing exponentially.

Let the population, P=P_0e^{bt}

where, P_0 and b are constants, t=(Current year -1994) is the time in years from 1994.

In 1994, t=0, the population of rabbit, P=9600, so

9600=P_0e^{b\times 0}

So, P_0=9600

and in 2000, t=2000-1994=6 years and population of the rabbit, P=18400

18400=9600 \times e^{b\times 6} \\\\\frac{18400}{9600}=e^{b\times 6} \\\\

\ln(23/12}=6b \\\\

b = \frac{\ln{1.92}}{6} \\\\

b=0.109

On putting the value of P_0 and b, the population of the rabbit after t years from 1994 is

P=9600 \times e^{0.109\times t}

In 2009, t= 2009-1994=15 years,

So, the population of the rabbit in 2009

P=9600 \times e^{0.109\times 15}=49243

Hence, the population of the rabbit in 2009 is 49243.

7 0
3 years ago
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