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Goshia [24]
2 years ago
13

the volume of the rectangular prism shown below is 96 cubic feet. The dimensions of the prism base are 4 feet and 3 feet. What i

s the prisms height in feet
Mathematics
1 answer:
g100num [7]2 years ago
7 0
Height=volume:base area
96:(4*3)= 96:12=8
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I'm new to this and I dont really understand this
agasfer [191]

Answer:

So starting off with 1a f(4)

We simply substitute x with 4 for the function

f(4)=2(4)-5

f(4)=8-5

f(4)=3

Next 1b, here it's a little different since you have to multiply the functions I think ( please correct me if I'm wrong).

gf(4), basically means functions g and f are being multiplied and their variables are being substituted with 4.

g(4)=4^2+3

g(4)=16+3

g(4)=19

and we also know from before that f(4)=3, so we'll do 19 times 3 which is 57

For the next two, I may be wrong, but I'm still going to try:

anything to the power of a negative is a fraction so for f^-1(x)=2x-5 we'll have 1/f(x)=x/2+5/2

And then for g^-1, we'll have 1/g(x)=\sqrt{x-3}  \sqrt{x-3}

Hope I helped :)

5 0
2 years ago
I'm confused, please help. :/
vampirchik [111]

uh i did this wrong so uh just ignore what i said

5 0
3 years ago
Read 2 more answers
An FM radio station broadcasts at 84 megahertz (MHz). What is the energy of each photon in Joule? Use h = 6.6 * 10 ^ (- 34) * j
iragen [17]

Answer:

E=5.544*10^{-26} J

Step-by-step explanation:

The equation for photon energy is given by:

E=hf

Where:

h=Planck\hspace{3}constant=6.6*10^{-34} \\f=Frequency\hspace{3}of\hspace{3}the\hspace{3}wave=84000000Hz

This equation telling us that the higher the frequency of the photon, the greater its energy. And the longer the photon wavelength, the lower its energy.

So, replacing the data provided in the previous equation:

E=(6.6*10^{-34} )*(84000000)=5.544*10^{-26} J

7 0
3 years ago
Prove that is here<br><img src="https://tex.z-dn.net/?f=1%20-%20cos%20%7B2%7Da%20%5Cdiv%201%20-%20sin%20a%7B2%7D%20%20%3D%20tan%
garri49 [273]

\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}

<h3>LHS</h3>

\boxed{\sf \dfrac{cosA}{sinA}=cotA}

\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}

\\ \sf\longmapsto 1-cot2A

\\ \sf\longmapsto 1-\dfrac{1}{tan2A}

\\ \sf\longmapsto \dfrac{tan2A-1}{tan2A}

\\ \sf\longmapsto tan2A

8 0
2 years ago
Pleeeeeaseeee HELPP
ElenaW [278]

Answer:

A

Step-by-step explanation:

8 0
2 years ago
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