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lana66690 [7]
3 years ago
9

Identify two properties of a cube that must be known in order to determine the density of a cube

Mathematics
1 answer:
snow_tiger [21]3 years ago
4 0
90% of people marry there 10th grade love. since you have read this, you will be told good news tonight. if you don't pass this on nine comments your worst week starts now this isn't fake. apparently if you copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes, and someone will say i love you. lol idk why im doing this
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Name collection boxes
kirill115 [55]
How would we do that here
4 0
4 years ago
(4.8x10x7) + 6,500,000 what is the value of the expression
Fiesta28 [93]

Answer:

=(48*7) +65*10^5

=((40+8) *7) +65*10^5

=(280+56)+65*10^5

=336+65*10^5

=.336*10^3+65*10^5

=.00336*10^5+65*10^5

=(.00336+65) *10^5

=64.00336*10^5

4 0
3 years ago
What is the product (4x)( -3x^6)(-7x^3)
11111nata11111 [884]

Answer:

  84x^10

Step-by-step explanation:

The coefficients multiply, and the exponents add.

  (4x)( -3x^6)(-7x^3) = (4)(-3)(-7)x^(1+6+3) = 84x^10

__

The rule for exponents is ...

  (x^a)(x^b) = x^(a+b)

7 0
3 years ago
Manuel bought 2kg of jelly beans and 2kg of gummy worms for a total of $26. Danny bought 2kg of jelly beans and 3kg of gummy wor
charle [14.2K]

Answer:

Jelly beans: $6 for 1 kg

Gummy worms: $7 for 1 kg

Step-by-step explanation:

In this question, we need to find the cost of 1kg of jelly beans and gummy worms.

To do this, make equations for both scenarios and solve:

2j + 2g = 26

2j + 3g = 33

Turn the bottom equation negative, as we will first solve for gummy worms (g).

2j + 2g = 26

-2j - 3g = -33

Solve:

-g = -7

Divide both sides by -1.

g = 7

We now know that gummy worms cost $7 for 1 kg

To solve for jellybeans (j), plug in 7 to g in one of the equations and solve:

2j + 2(7) = 26

2j + 14 = 26

Subtract 14 from both sides.

2j = 12

Divide both sides by 2.

j = 6

Jellybeans cost $6 for 1 kg.

Check answer by plugging in values to one of the equations:

2(6) + 2(7) = 26

12 + 14 = 26

26 = 26

3 0
3 years ago
Find two consecutive whole numbers such that 4/7 of the larger exceeds 1/2 of the smaller by 5
Darina [25.2K]

Answer:

The consecutive numbers are 62 and 63

Step-by-step explanation:

Let the larger number be represented by x and the smaller number by y,

Provided they are consecutive numbers;

x = y + 1 --- Equation 1

From the question; we have that

\frac{4x}{7} = \frac{y}{2} + 5 --- Equation 2

Required

Find x and y

Multiply both sides of equation 2 by 14

14 * \frac{4x}{7} = 14 * \frac{y}{2} + 14 * 5

2 * 4x = 7 * y + 70

8x = 7y + 70 ---- Equation 3

Substitute y + 1 for x in equation 2

8(y + 1) = 7y + 70

Open bracket

8y + 8 = 7y + 70

Collect like terms

8y - 7y = 70 - 8

y = 62

x = y + 1

So,

x = 62 + 1

x = 63

Hence, the consecutive numbers are 62 and 63

8 0
3 years ago
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