Solve for x: 3|x-3| 2=14 a. No solution b. x=-1,x=8.3 c. x=0,x=7 d. x=-1,x=7

1 answer:

3 0

I am looking on the answers, and there is only one case, when a or b or c or d pass: 3|x-3| + 2 = 14. So I assume, that before two is plus. Then:

3|x-3|+2=14 |minus 2
3|x-3|=12 |divide 3
|x-3|=4

From absolute value definition you've got two ways:

x-3=4 or x-3=-4
x=7 or x=-1

And answer d) passes

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A dealer sold 200 tennis racquets. Some were sold for $33 each, and the rest were sold on sale for $18. The total receipts form

Mumz [18]

120 tennis racquets were sold for $ 18 each

Solution:

Let x = number that sell for $18 each

Then, 200 - x = number that sell for $33 each

The total receipts form these sales were 4800 dollars

Thus we frame a equation as:

number that sell for $18 each x 18 + number that sell for $33 each x 33 = 4800

$x \times 18 + (200-x) \times 33 = 4800\\\\Solve\ the\ above\ equation\ for\ x\\\\18x + 6600 - 33x = 4800\\\\Move\ the\ variables\ to\ one\ side\\\\18x-33x = 4800-6600\\\\-15x = -1800\\\\Divide\ both\ sides\ of\ equation\ by\ -15\\\\x = 120$