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Delvig [45]
4 years ago
8

Pleaseeee help!!! I will mark you as brainlinest for correct answer!!!!

Mathematics
1 answer:
Maru [420]4 years ago
8 0
Evaluate the function at 2. That is f(2).
Evaluate the function at 0. That is f(0).

the average rate of change from 0 to 2 is (f(2) - f(0))/(2 - 0)

f(x) = 120(0.1)^x

f(2) = 120(0.1)^2 = 120 * 0.01 = 1.2

f(0) = 120(0.1)^0 = 120 * 1 = 120

average rate of change = (1.2 - 120)/(2 - 0) = -118.8/2 = -59.4
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Simplify: <br><br> 3c-5d+5d<br><br> Pls
Arturiano [62]

Answer:

3 c

Step-by-step explanation:

Simplify the following:

5 d - 5 d + 3 c

Hint: | Combine like terms in 5 d - 5 d + 3 c.

5 d - 5 d = 0:

Answer: 3 c

5 0
4 years ago
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mixas84 [53]
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A rectangle has the following vertices. Find the area of the rectangle. (9, −1), (−1, 7), (−5, 2), (5, −6)
stiks02 [169]

Answer:  82 sq. units .

Step-by-step explanation:

Let A (9, −1), B (−1, 7), C(−5, 2), D(5, −6) are the vertices of rectangle.

Then we plot them on graph ( as provided in attachment)

Length = AB =\sqrt{(9+1)^2+(-1-7)^2} units  [By distance formula : \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]

=\sqrt{(10)^2+(-8)^2}=\sqrt{100+64}=\sqrt{164}=2\sqrt{41} units

Width = BC = \sqrt{(-1+5)^2+(7-2)^2} units

=\sqrt{4^2+5^2}\\\\=\sqrt{16+25}\\\\=\sqrt{41}

Area = length x width

= 2\sqrt{41}\times\sqrt{41}=2\times41= 82\text{ sq. units}

Hence, the  area of the rectangle is 82 sq. units .

7 0
3 years ago
More than half of the students were excited about the project. In fact, were excited. If 10 students were not
alina1380 [7]

Answer:1/2 divided by 10

Step-by-step explanation:

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Answer:

J(2, 5 )

Step-by-step explanation:

Using the section formula

x_{J} = \frac{1(-2)+2(4)}{2+1} = \frac{-2+8}{3} = \frac{6}{3} = 2

y_{J} = \frac{1(1)+2(7)}{2+1} = \frac{1+14}{3} = \frac{15}{3} = 5

Thus J = (2, 5 )

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3 years ago
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