This is just the number of permutations of the set {0, 0, 0, 1, 1, 1, 2, 2, 2}. There are 9 elements in the set, so there are 9! = 362,880 possible ternary strings with exactly 3 each of 0, 1, and 2.
Answer:
4x^2-12x+9 hope this helps
Step-by-step explanation:
Domain is f(x) > 0
range is x is any real number
Its 2 because u see how many 4s go into 8
Answer:
B. 3×7×7
Step-by-step explanation:
147
49 * 3
7 * 7 * 3
