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3 years ago

HELP PLZ 30 POINTS!

Mathematics

1 answer:

solmaris [256]3 years ago

5 0

I'm so sorry I don't know maybe you have a pic of the question

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The blades of a windmill turn on an axis that is 35 feet above the ground. The blades are 10 feet long and complete two rotation

Alona [7]

Answer:

h = 10sin(π15t)+35

Step-by-step explanation:

The height of the blade as a function f time can be written in the following way:

h = Asin(xt) + B, where:

B represets the initial height of the blade above the ground.

A represents the amplitud of length of the blade.

x represents the period.

The initial height is 35 ft, therefore, B = 35ft.

The amplotud of lenth of the blade is 10ft, therefore A = 10.

The period is two rotations every minute, therefore the period should be 60/4 = 15. Then x = 15π

Finally the equation that can be used to model h is:

h = 10sin(π15t)+35

5 0

3 years ago

Read 2 more answers

The equation y - 2 = 3(x + 1) is in point-slope

attashe74 [19]

Y-2=3x+3
Then add two
So y=3x+5
Hope this helps sorry if wrong

5 0

3 years ago

how many restaurants have hawaiin pizza on their menu if 7.5% of the 100 restaurants served hawaiin pizza

vova2212 [387]

By my, calculations this means that there is an estimated number of restaurants that receive a Hawaiian pizza order from their menu and that is 7.5. So out of 100 restaurants, there are 7.5 Hawaiian pizza orders.

4 0

3 years ago

Read 2 more answers

he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s

sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

$P(X$

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) = $[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]$

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

$NORMSDIST(6.366)-NORMSDIST(-1.47)$

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = $P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]$

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0

2 years ago

PLS ANSWER <br> I WILL MARK AS BRAINLIST

marysya [2.9K]

Answer:

Option 3

Step-by-step explanation:

This may not be the most efficient way, but I solved each one and option 3 had the same answer as the question.

8 0

2 years ago