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tankabanditka [31]
3 years ago
9

The mass of an object is 12g and its volume is 6cm3. What is its density? *

Mathematics
1 answer:
Cloud [144]3 years ago
3 0

Answer:

i think 2 g/cm3

Step-by-step explanation:

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Estimate 32% of 19.
Kipish [7]

Answer: 13

Step-by-step explanation: calculator

5 0
3 years ago
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Which number is the additive inverse of -5?
elena-14-01-66 [18.8K]

Answer:

5

Step-by-step explanation:

-5 + 5 = 0

4 0
3 years ago
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A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.
tatyana61 [14]

Answer:

(a)g(n)=0.05\cdot 2^n

(b)g^{-1}(n)=\log_{2}20g(n)

(c)43 times

Step-by-step explanation:

<u>Part A</u>

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n

<u>Part B</u>

<u />g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)<u />

<u />

<u>Part C</u>

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

3 0
3 years ago
PLEASE HELP
Sergeeva-Olga [200]

Answer:

y = 2

Step-by-step explanation:

I will solve this problem, using the elimination method.

-2(5x - 3y) = -11

-10x + 6y = 22

2x - 6y = -14

Subtract and divide for x

-8x = 8

x = -1

Input -1 into the equations

2(-1) - 6y = -14

-6y - 2 = -14

-6y = -12

y = 2

Thanks!

5 0
3 years ago
Lily weighs 57.7 kg while her sister weighs 59.02 kg, how much more does Lily's sister weigh then her? Please provide the calcul
PilotLPTM [1.2K]

The answer is 1.32

For this calculation, assuming that no conversions are required, the calcitonin goes as follows:


All that is needed is to subtract 57.7 from 59.02.

59.02 - 57.7 = ?

59.02 - 57.7 = 1.32

Hope this helps! Have a great day.
5 0
3 years ago
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