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dem82 [27]
3 years ago
11

There are 5 very different seats in a car. In how many ways can 5 different people be seated in the car for a road trip if only

2 of them know how to drive?
Mathematics
1 answer:
avanturin [10]3 years ago
6 0

Answer:

48

Step-by-step explanation:

Let A and B be the two people who are able to drive. If A is driving, there are 4! ways to arrange the remaining peoplein the car seats. If B is driving, there are also 4! ways to arrange the remaining people. The number of arrangements 'n' is:

n=2*4!\\n=2*4*3*2*1\\n=48\ ways

They can be arranged in 48 ways.

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Hello :
f(-4) = 4(-4)+9 = -7
f(-2) = 4(-2)+9 = 1
f(0) = 4(0)+9 = 9
f(2) = 4(2)+9 = 17
the range of the function f(x) = 4x + 9 is : <span>D' = {-7, 1, 9, 17}</span>
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Michael drove 0.5 miles. How many inches did he travel?
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