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dem82 [27]
3 years ago
11

There are 5 very different seats in a car. In how many ways can 5 different people be seated in the car for a road trip if only

2 of them know how to drive?
Mathematics
1 answer:
avanturin [10]3 years ago
6 0

Answer:

48

Step-by-step explanation:

Let A and B be the two people who are able to drive. If A is driving, there are 4! ways to arrange the remaining peoplein the car seats. If B is driving, there are also 4! ways to arrange the remaining people. The number of arrangements 'n' is:

n=2*4!\\n=2*4*3*2*1\\n=48\ ways

They can be arranged in 48 ways.

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Use the properties of exponents to rewrite the expression.<br> (-3yz)(-3yz)(-3yz)(-3yz)
Lera25 [3.4K]

Answer:

Answer is 81y^4z^4

Step-by-step explanation:

The expression is (-3yz) (-3yz) (-3yz) (-3yz).

Since all the four terms have power 1:

(-3yz)^1 (-3yz)^1 (-3yz)^1 (-3yz)^1

We know that we can add the powers if the terms have same base

So,

=(-3yz)^1+1+1+1

=(-3yz)^4

=(-3)^4(y)^4(z)^4.

If the power is an even number than the negative sign changes into positive sign.

=3^4y^4z^4

=81y^4z^4

Thus the answer is 81y^4z^4....

3 0
3 years ago
Algebra 2<br> How do I solve this problem
Doss [256]

Answer:

Step-by-step explanation:

You cannot solve the problem because it doesn't have an equal sign, but I suppose you can simplify it. Look at this screenshot, it may help:

5 0
3 years ago
Read 2 more answers
You have a set of nested boxes whose lengths vary directly with their widths. One box is 2.5 in, wide and 5.5 in. long. A second
Anna11 [10]

Answer:

B

Step-by-step explanation:

If you're looking for direct correlation, you're looking for a proportion for the second box. So you set the ratio of 2.5:5.5 up as a fraction. 2.5/5.5 and set it equal to the second box 3/x.

2.5     =      3

5.5             x

cross multiply

16.5=2.5x

and divide

16.5/2.5 and you get your answer

7 0
3 years ago
Which number is an irrational number? A. B. C. D.
Ivahew [28]
There’s nothing so let’s just go with C
6 0
3 years ago
Identify the center and radius for the circle with the following equation; (x+5)^2+y^2+12y=3
rosijanka [135]
Center: (-5,-6)
Radius: 39
How to do it

Complete the square for
y
2
+
12
y
y
2
+
12
y
.

(
y
+
6
)
2
−
36
(
y
+
6
)
2
-
36
Substitute
(
y
+
6
)
2
−
36
(
y
+
6
)
2
-
36
for
y
2
+
12
y
y
2
+
12
y
in the equation
(
x
+
5
)
2
+
y
2
+
12
y
=
3
(
x
+
5
)
2
+
y
2
+
12
y
=
3
.
(
x
+
5
)
2
+
(
y
+
6
)
2
−
36
=
3
(
x
+
5
)
2
+
(
y
+
6
)
2
-
36
=
3
Move
−
36
-
36
to the right side of the equation by adding
36
36
to both sides.
(
x
+
5
)
2
+
(
y
+
6
)
2
=
3
+
36
(
x
+
5
)
2
+
(
y
+
6
)
2
=
3
+
36
Add
3
3
and
36
36
.
(
x
+
5
)
2
+
(
y
+
6
)
2
=
39
(
x
+
5
)
2
+
(
y
+
6
)
2
=
39
This is the form of a circle. Use this form to determine the center and radius of the circle.
4 0
3 years ago
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