Speed of the east bound cyclist is 12 mph and the speed of west bound cyclist is 15 mph.
<u>Solution:</u>
Let us assume that x is speed of slower eastbound cyclist
So, x+3 will be the speed of faster westbound cyclist
We know that distance is the product of speed and time. That is,

West-bound DATA:
Rate of speed = x+3 mph ; Time = 6 hrs ; distance = 6(x+3) = 6x+18 miles
East-bound DATA:
Rate of speed = x mph ; time = 6 hrs. ; distance = 6x miles
On solving,
Distance apart = 162



So, the rate of speed of the east bound cyclist is 12 mph and the rate of speed of the west bound cyclist will be 
Welcome HAHHAHAHAHAHAHAHHAHAHAHAHHAHAHA
I believe that x=4 would be the answer
It would take them a half and hour