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18$-8$book=20pencils that were 10$.
and Brian had 80 cards work: 80÷2= 40+10 new cards=50 cards
Answer:
Step-by-step explanation:
Given that you have eight cards. Five are green and three are yellow. The five green cards are numbered 1, 2, 3, 4, and 5. The three yellow cards are numbered 1, 2, and 3. The cards are well shuffled. You randomly draw one card.
G = card drawn is green
Y = card drawn is yellow
E = card drawn is even-numbered
List:
Sample space = {G1, G2, G3, G4, G5, Y1, Y2, Y3}
2) P(G) = 5/8
3) P(G/E) = P(GE)/P(E)
GE = {G2, G4}
Hence P(G/E) = 2/5
4) GE = {G2, G4}
P(GE) = 2/8 = 1/4
5) P(G or E) = P(G)+P(E)-P(GE)
= 5/8 + 3/8-2/8 = 3/5
6) No there is common element as G2 and G4
Cannot be mutually exclusive
Step-by-step explanation:
If the two chords are congruent, then they must be equidistant from the centre of the circle.
Answer: <u><em>D) They must be perpendicular</em></u>
A is rejected because the chord might not pass through the center of the circle.
B is rejected because the chords are not obligated to be parallel.
C is rejected because it is not compulsory for the chords to be perpendicular.
Question 5 (1 point) What is the mean of this set of data: 78, 79, 80, 80, 89, 89, 92, 93, 94, 95, 95, 95 Round your answer to t
Len [333]
88.3
add all the numbers, you get 1,059 and divide that by how many numbers there are which is 12 and you get 88.3
