If the value of a is negative, then the range will be (-∞, k) and if the value of the a is positive then the range will be (k, ∞).
<h3>What is a quadratic equation?</h3>
It's a polynomial with a worth of nothing.
There exist polynomials of variable power 2, 1, and 0 terms.
A quadratic condition is a condition with one explanation where the degree of the equation is 2.
Domain and range of linear and quadratic functions
Let the linear equation be y = mx + c.
Then the domain and the range of the linear function are always real.
Let the quadratic equation will be in vertex form.
y = a(x - h)² + k
Then the domain of the quadratic function will be real.
If the value of a is negative, then the range will be (-∞, k) and if the value of the a is positive then the range will be (k, ∞).
More about the quadratic equation link is given below.
brainly.com/question/2263981
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Answer:
Multiply the area of the base by the height and divide by 3.
Step-by-step explanation:
V = (1/3)Bh
where B = area of the base, and
h = height
Answer: Multiply the area of the base by the height and divide by 3.
Answer:
432 in.^2
Step-by-step explanation:
The side of the suitcase is a rectangle. One length is 24 inches. The diagonal of the rectangle is 30 inches long. The diagonal is a hypotenuse of a right triangle. The length is a leg. We need to find the other leg.
We use the Pythagorean theorem,
a^2 + b^2 = c^2
(24 in.)^2 + b^2 = (30 in.)^2
576 in.^2 + b^2 = 900 in.^2
b^2 = 324 in.^2
b = sqrt(324 in^2)
b = 18 in
area of rectangle = length * width
A = 24 in. * 18 in.
A = 432 in.^2
Answer: $1,780
Step-by-step explanation:
Joy Wigens deposited 1/3 of the check of $2,670 that she received in her Citibank account.
The amount she deposited in her Citibank account was:
= 1/3 * 2,670
= $890
The amount she is left with after this deposit will therefore be:
= Check amount - deposit at Citibank
= 2,670 - 890
= $1,780
Answer:
I) |xz| ≈ 28.6 km
II) |yz| ≈ 34.8 km
Step-by-step explanation:
Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)
|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°
Using Trigonometric ratio - SOHCAHTOA
I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20
|xz| = 20 * Tan 55 = 20 * 1.428
|xz| = 28.56 km
|xz| ≈ <u>28.6 km</u>
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II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|
|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°
|yz| = 20 ÷ 0.574 = 34.84 km
|yz| ≈ <u>34.8 km</u>
