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uranmaximum [27]
3 years ago
13

The perimeter of the figure is 70 ft how long are the unknown sides?

Mathematics
1 answer:
Rina8888 [55]3 years ago
3 0

Answer:

The unknown sides (x) are 6 ft. long

Step-by-step explanation:

Add it all together:

x+x+5+7+10+10+12+14=70

Simplify a little more:

2x+58=70

Subtract 58 from both sides

2x+58 -58=70-58

Solve

2x=12

Divide by 2 on both sides

2/2x=12/2

Solve

x = 6

The unknown sides (x) are 6 ft. long

Have a nice day!

If this helped please mark as brainiest :)

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Factorize 6ab-15bc-16cd+4ab​
balu736 [363]

Answer:

mommymommymoomamayeahyeah

4 0
3 years ago
PLEASE may I get help, I'm so lost. It would mean a lot to me, please.
MrMuchimi

9514 1404 393

Answer:

  1. 80
  2. 40
  3. 10 to 20, inclusive

Step-by-step explanation:

1. The various goals can be met without filling the theater. This fact means there is a range of possibilities for each of the answers. However, we take the wording, "because of the demand for tickets ..." to mean demand is high and the theater will be sold out.

Since two children's tickets will be sold for each adult ticket sold, the number of children's tickets is 2/3 of the total.

  children's tickets = 2/3 × 120 = 80

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2. The remaining 40 tickets will be adult tickets.

  40 adult tickets will be sold.

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3. The total revenue must be at least $1800. If we allow 'd' tickets to be sold at a discount, then we can find the limits on d using the inequality ...

  24(40-d) +24(0.75)d +12(80) ≥ 1800 . . . . revenue from ticket sales

  -6d ≥ -120 . . . . . . . . . . . . . . . . . . . collect terms, subtract 1920

  d ≤ 20 . . . . . . . . . . divide by -6

  At least 10 and at most 20 adult tickets can be sold with a discount.

("At least 10" comes from the problem requirements.)

4 0
3 years ago
a ladder 10cm rest on a vertical wall of 8cm what is the distance of the vertical Wall from the Foot of the ladder ​
ira [324]

Hi there!

\huge\boxed{6cm}

We can use the Pythagorean Theorem to solve:

Use the formula a² + b² = c² where:

"a" and "b" are the legs

"c" = Hypotenuse

The diagonal side, or the length of the ladder is 10cm, and one of the legs of the triangle is 8cm, therefore:

(8)² + b² = 10²

64 + b² = 100

Subtract 64 from both sides:

b² = 36

Take the square root of both sides:

√b² = √36

b = 6 cm. This is the distance of the wall from the foot of the letter.

Edit: Typo.

6 0
3 years ago
Read 2 more answers
1.5d+3.25=1+2.25d. What is d?
DochEvi [55]
Simplifying
1.5d + 3.25 = 1 + 2.25d

Reorder the terms:
3.25 + 1.5d = 1 + 2.25d

Solving
3.25 + 1.5d = 1 + 2.25d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2.25d' to each side of the equation.
3.25 + 1.5d + -2.25d = 1 + 2.25d + -2.25d

Combine like terms: 1.5d + -2.25d = -0.75d
3.25 + -0.75d = 1 + 2.25d + -2.25d

Combine like terms: 2.25d + -2.25d = 0.00
3.25 + -0.75d = 1 + 0.00
3.25 + -0.75d = 1

Add '-3.25' to each side of the equation.
3.25 + -3.25 + -0.75d = 1 + -3.25

Combine like terms: 3.25 + -3.25 = 0.00
0.00 + -0.75d = 1 + -3.25
-0.75d = 1 + -3.25

Combine like terms: 1 + -3.25 = -2.25
-0.75d = -2.25

Divide each side by '-0.75'.
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Simplifying
d = 3
7 0
4 years ago
Read 2 more answers
Write 256 as a product of prime factors
Kipish [7]
256 -> 4 -> 2 & 2
       -> 64 -> 8 & 8
8 -> 4 & 2
4 -> 2 & 2
8 -> 4 & 2
4 -> 2 & 2
(I hope this format makes sense) So you are left with 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 or 2^{8}. I hope this helps!
6 0
3 years ago
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