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erma4kov [3.2K]

3 years ago

10

the scale on a map is 2 cm :65 mi. The actual distance between two cities is 125 miles. What is the distance between the two cit

ies on a map

1 answer:

Sophie [7]3 years ago

4 0

125/65= about 1.92 cm

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Graph the image of the given triangle under a dilation with a scale factor of -3 and center of dilation (0,0).

Svetlanka [38]

The points would be (9,9) , (0,-6) , (6,-9)
I hope this helps !

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4 years ago

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Bella needs to read three chapters of her book. If she reads 3/5 of a chapter each night, how many nights will it take her to re

konstantin123 [22]

It will take her 5 nights to read three chapters.

Take $\frac{3}{5}$ and add up until you get to 3.

1st night: 3/5

2nd night: 1 1/5

3rd night: 1 4/5

4th night: 2 2/5

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4 years ago

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Multiply and simplify: sq rt 7x ((sq rt x)-7sq rt. 7)

jarptica [38.1K]

7x(√x - 7√7) Multiply √7x to "√x" and "-7√7" respectively:
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After simplifying the equation, I got the answer x√7 - 49√x.

3 0

3 years ago

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The probability that a lab specimen contains high levels of contamination is 0.10. A group of 4 independent samples are checked.

galben [10]

Answer:

a) 0.6561

b) 0.2916

c) 0.3439

Step-by-step explanation:

We are given the following information:

Let us treat high level of contamination as our success.

p = P(High level of contamination) = P(success) = 0.10

n = 4

The, by binomial distribution:

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}\\\text{where x is the number of success}$

a) P(No high level of contamination)

We put x = 0, in the formula.

$P(X=0) = \binom{4}{0}.(0.10)^0.(1-0.10)^{4} =0.6561$

Probability that no lab specimen contain high level of contamination is 0.6561

b) P(Exactly one high level of contamination)

We put x = 1, in the formula.

$P(X=1) = \binom{4}{1}.(0.10)^1.(1-0.10)^{3} =0.2916$

Probability that no lab specimen contain high level of contamination is 0.6561

c) P(At least one contains high level of contamination)

$p(x \geq 1) = 1 - p( x = 0) = 1 - 0.6561 = 0.3439$

Probability that at least 1 lab specimen contain high level of contamination is 0.3439

8 0

3 years ago

What is the greatest common factor of the terms 14c to the second power D and 42 C to the third power d

irina [24]

Answer:

Step-by-step explanation:

To find the GCF we factor all the given terms and then find the Greatest Common Factor from both ,

So , The given two terms can be given by

$14c^2d = 2.7.c.c.d\\42c^3d =2.3.7.c.c.c.d\\$

Here common numbers that are in both are

2.7.c.c.d

so GCF= $14c^2d$

7 0

3 years ago