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3 years ago

Mr. McGee has a piece of yarn that is 19 inches long. He cuts off 2 pieces that

Mathematics

2 answers:

Phoenix [80]3 years ago

6 0

7 because 19-6-6 or 19-12 because 6+6=12 the answer is 7

Leviafan [203]3 years ago

4 0

Answer:

Step-by-step explanation:

19 - 2(6) = 19-12= 7

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Number 10 plzz???????

WARRIOR [948]

%error=(6.5g/mol - 7g/mol)/(7g/mol) * 100= 7.14% error

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2 years ago

How many bases does a triangular pyramid have?

MAVERICK [17]

1 base. The triangular pyramid has 1 base, and that is the square at the bottom. Hope this helps.

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3 years ago

a 1ft long piece of wire needs to be divided into two pieces which will form the shape of a circle and a square. Determine the l

yan [13]

Answer:

Length of wire for circle is 0.44 ft

Length of wire for square is 0.56 ft

Step-by-step explanation:

Let x is circumference of the circle

then

(1-x) = perimeter of the square

Find the radius of the circle

r = (x/2.π)

Find the area of the circle

a = π(x/2π)^2

a = π(x^2/4π^2)

Cancel π

a = x^2/4π

Find the area of the square:

a = (1-x/4)^2

a = (1-2x+x^2)/16

Total area

A = (x^2/4π)+(1-2x+x^2/16)

A = 4x^2+3.142-6.284x+3.142x^2

A = 7.142x^2-6.284x+3.142

Find the axis of symmetry [x = -b/(2a)]

x = -(-6.284)/{2.(7.142)}

x = 6.284/14.284

x = 0.44 ft, the piece of wire creating a circle

and

1 - 0.44 = 0.56 ft, the piece of wire creating the square

These lengths should give minimum area of the circle and square together

7 0

2 years ago

Identify the y intercept and asymptote of the graph of the exponential function. y=3^x

nalin [4]

Y intercept is (0,1)
horizontal asymptote

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3 years ago

30 POINTS,NEED HELP ASAP !!!

zaharov [31]

Answer: OPTION A.

Step-by-step explanation:

You can observe that in the figure CDEF the vertices are:

$C(-2,-1),\ D(-2,0),\ E(2,2)\ and\ F(2,1)$

And in the figure C'D'E'F' the vertices are:

$C'(-8,-4),\ D'(-8,0),\ E'(8,8)\ and\ F'(8,4)$

For this case, you can divide any coordinate of any vertex of the figure C'D'E'F' by any coordinate of any vertex of the figure CDEF:

For C'(-8,-4) and C(-2,-1):

$\frac{-8}{-2}=4\\\\\frac{-4}{-1}=4$

Let's choose another vertex. For E'(8,8) and E(2,2):

$\frac{8}{2}=4\\\\\frac{8}{2}=4$

You can observe that the coordinates of C' are obtained by multiplying each coordinate of C by 4 and the the coordinates of E' are also obtained by multiplying each coordinate of E by 4.

Therefore, the rule that yields the dilation of the figure CDEF centered at the origin is:

$(x, y)$ → $(4x, 4y)$

7 0

3 years ago

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