Question

Find the angles of a parallelogram in which an exterior angle is one-third that its interior angle.​

Answer 1

Answer:

The angles of a parallelogram are 135°-45°-135°-45°

Step-by-step explanation:

we know that

In a parallelogram opposites angles are congruent and consecutive angles are supplementary

Remember that  

The sum of a exterior angle and its interior angle is equal to 180 degrees

Let

x ----> the measure of one interior angle of parallelogram

y ----> the measure of the other interior angle of  parallelogram

we have that

$x+\frac{x}{3}=180^o$

solve for x

$\frac{4}{3}x=180^o\\\\x=(180^o)3/4\\\\x=135^o$

Find the measure of the other interior angle of parallelogram

Remember that consecutive interior angles are supplementary

$x+y=180^o$

substitute the value of x

$135^o+y=180^o$

solve for y

$y=45^o$

therefore

The angles of a parallelogram are 135°-45°-135°-45°