Answer with Step-by-step explanation:
The height of the ball from the ground as a function of time is given by

The height of the ball at any instant of time can be found by putting the value of time 't' in the above relation as
Part a)
Height of ball after 2 seconds it is released is

Part b)
Height of ball after 4 seconds it is released is

Answer:
1/10
Step-by-step explanation:
1/2 * 1/5
Multiply the numerators
1*1 = 1
Multiply the denominators
2*5 =10
Numerator over denominator
1/10
Answer:
A.-3/7
Step-by-step explanation:
the slope formula is
m = (y2 - y1) / (x2-x1)
The point (4, 2) is (x1, y1) and the point (-3, 5) is (x2, y2). Now you have to substitute in the slope formula:
m = (5 - 2) / (-3 - 4)
m = 3 / -7
m = -3/7
Answer:
Equation of tangent plane to given parametric equation is:

Step-by-step explanation:
Given equation
---(1)
Normal vector tangent to plane is:


Normal vector tangent to plane is given by:
![r_{u} \times r_{v} =det\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\cos(v)&sin(v)&0\\-usin(v)&ucos(v)&1\end{array}\right]](https://tex.z-dn.net/?f=r_%7Bu%7D%20%5Ctimes%20r_%7Bv%7D%20%3Ddet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7Bk%7D%5C%5Ccos%28v%29%26sin%28v%29%260%5C%5C-usin%28v%29%26ucos%28v%29%261%5Cend%7Barray%7D%5Cright%5D)
Expanding with first row

at u=5, v =π/3
---(2)
at u=5, v =π/3 (1) becomes,



From above eq coordinates of r₀ can be found as:

From (2) coordinates of normal vector can be found as
Equation of tangent line can be found as:

So since this is a linear equation, which is y=mx+b, you use what it tells you in the word problem. so mx is the rate, since in this equation 200 per ton of sugar that's your mx, so its 200x. then for your b value, which in this case is the cost of truck rental, so its 5,400.
your equation is C=200s+5400
the variables are the same so you can use Y and X, but I used the variables used in the word problem.
Y=200x+5400