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BigorU [14]
3 years ago
10

Josephina is four years younger than Cameron and the sum of their ages is 88. write an equation and solve it to figure out their

ages. How old are Josephina and Cameron?
Mathematics
2 answers:
slavikrds [6]3 years ago
3 0
Josephina is 42 and Cameron is 46. The equation is 42 plus 46 = 88.
WARRIOR [948]3 years ago
3 0
Josephina’s age = J
Cameron’s age = C

C-J = 4
C+J = 88

Solve for C in the first equation
C=4+J

Substitute
(4+J)+J=88
4+ 2J = 88
2J = 84
J = 42

Then plug that back in
C= 4+42
C=46

Josephina is 42 and Cameron is 46
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Step-by-step explanation:

\underline{\underline{\sf{➤\:\:Solution}}}

\sf \dashrightarrow \:  \dfrac{ \left(\left(12 \right)^{ - 1}  + \left(13 \right)^{ - 1}  \right) }{\left( \dfrac{1}{5}\right) ^{ - 2}  \times\left( \left( \dfrac{1}{5}  \right) ^{ - 1}  +\left( \dfrac{1}{8}  \right) ^{ - 1}  \right) ^{ - 1}}

\sf \dashrightarrow \:  \dfrac{ \left(\dfrac{1}{12}  + \dfrac{1}{13} \right) }{\left( \dfrac{5}{1}\right) ^{ 2}  \times\left( \dfrac{5}{1}  + \dfrac{8}{1}   \right) ^{ - 1}}

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\sf \dashrightarrow \:  \dfrac{ \left(\dfrac{1 \times 13 = 13}{12 \times 13 = 156}  + \dfrac{1 \times 12 = 12}{13 \times 12 = 156} \right) }{\ \dfrac{25}{1} \times\left( \dfrac{5 + 8}{1}    \right) ^{ - 1}}

\sf \dashrightarrow \:  \dfrac{ \left(\dfrac{13}{156}  + \dfrac{12}{156} \right) }{\ \dfrac{25}{1} \times\left( \dfrac{13}{1}    \right) ^{ - 1}}

\sf \dashrightarrow \:  \dfrac{ \left(\dfrac{13 + 12}{156}  \right) }{\ \dfrac{25}{1} \times\dfrac{1}{13} }

\sf \dashrightarrow \:    \dfrac{25}{156} \div    \dfrac{25}{13}

\sf \dashrightarrow \:    \dfrac{ \cancel{25}}{156}  \times    \dfrac{13}{ \cancel{25} }

\sf \dashrightarrow \:     \dfrac{13}{156}

\sf \dashrightarrow \:     \dfrac{1}{12}

\sf \dashrightarrow \:    Answer =   \underline{\boxed{ \sf{ \dfrac{1}{12} }}}

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\sf Case : (i) \: if \: a > b \: then, \bigg( \dfrac{m}{n}\bigg) ^{a} \div \bigg( \dfrac{m}{n}\bigg)^{b} = \bigg( \dfrac{m}{n}\bigg)^{a - b}

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\sf \: 5^{th} \: Law = \bigg( \dfrac{m}{n} \bigg)^{0} = 1

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