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3 years ago

PLEASE HELP ME. thx

Mathematics

1 answer:

AfilCa [17]3 years ago

5 0

cant tell direct message me a better picture please

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Someone please help!! i will make you a brainliest...i don’t want to fail:(((

Serggg [28]

Answer:

the fisrt one is y=1/2x

the second one is y=x+11

the third one is y= x^3

fourth on is y= ^3 checkmark x

Step-by-step explanation: your welcome

8 0

2 years ago

The width of a container is 5 feet less than its height. Its length is 1 foot longer than its height. The volume of the containe

juin [17]

The height of container is 8 feet

Solution:

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

The volume of container is given as:

$v = length \times width \times height$

Given that volume of the container is 216 cubic feet

$216 = l \times w \times h$

Substitute eqn 1 and eqn 2 in above formula

$216 = (1 + h) \times (h-5) \times h\\\\216 = (h+h^2)(h-5)\\\\216 = h^2-5h+h^3-5h^2\\\\216 = h^3-4h^2-5h\\\\h^3-4h^2-5h-216 = 0$

Solve by factoring

$(h-8)(h^2+4h+27) = 0$

Use the zero factor principle

If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

$h - 8 = 0\\\\h = 8$

Also,

$h^2+4h+27 = 0$

Solve by quadratic equation formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}$

$h = \frac{-4+\sqrt{4^2-4\cdot \:1\cdot \:27}}{2}=\frac{-4+\sqrt{92}i}{2}$

Therefore, on solving we get,

$h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i$

Thus solutions of "h" are:

h = 8

$h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i$

"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

8 0

3 years ago

The vertex of an isosceles triangle measures 15 degrees more than one of its base angles how many degrees are there in a base an

Alexxandr [17]

V=B+15
V+2B=180
Therefore:
3B+15=180
B=55
V=70

Check:
V+2B=180
70+2(55)=180
70+110=180
180=180. Checks.

5 0

3 years ago

Jacob wants to use an elevator to carry identical packages having the same weight. Each package weighs 3 pounds and Jacob weighs

omeli [17]

(300-99) /3 - the remainder =n

6 0

3 years ago

Read 2 more answers

What is the area of the figure? The diagram is not drawn to scale.

Veronika [31]

The picture in the attached figure

we know that
the figure is a parallelogram
the area of parallelogram=base*height
in this problem
base=34 in
height=35 in
so
area=34*35----> area=1190 in²

the answer is
A. 1,190 in^2

4 0

3 years ago