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andreyandreev [35.5K]
3 years ago
9

In a bag of oranges, the ratio of the good ones to the bad ones is 5:4. If the number of bad ones in the bag is 36, how many ora

nges are there altogether?
Mathematics
1 answer:
Advocard [28]3 years ago
5 0

5x - good ones

4x - bad ones

4x=36\\
x=9\\\\
5x=5\cdot9=45\\\\
45+36=81

<u>81</u>

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Line 1 passes through the points A(-15,-8) and B(-3,0). Line 2 has
Katyanochek1 [597]

Answer:

The equation of line 3 is;

y = \frac{2}{3} x + 6

Step-by-step explanation:

Line 1 passes through the points A(-15,-8) andn B(-3,0)

Line 2 has equation shown below;

5x - 3y + 18 = 0

Line 3 is parallel to line 1 and has the same y-intercept as line 2.

We are to determine the equation of line 3.

<u>Equation of line 1:</u>

<u />

Slope = change in y-axis ÷ change in x-axis

The slope of line 1 = \frac{0 - -8}{-3 - -15}  = \frac{8}{12} = \frac{2}{3}

Picking another point (x,y) on the line;

Slope = \frac{y - 0}{x - -3}  = \frac{2}{3}

y = \frac{2}{3} x + 2 (this is the equation of line 1)

<u>Equation of line 2:</u>

<u />

We put the equation given, of line 2, in the cartesian plane format;

3y = 5x + 18

y = \frac{5}{3} x + 6

Finally, the equation of line 2 is;

y = 1\frac{2}{3} x + 6

<u>Equation of line 3:</u>

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Given: Line 3 is parallel to line 1

The slopes of two parallel lines are the same so line 3 has a slope of \frac{2}{3}

Given: Line 3 has the same y-intercept as line 2

The y-intecept of line 2 is 6 (y-intercept is the value of y when x = 0)

So the equation of line 3 is;

y = \frac{2}{3} x + 6

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3 years ago
This is one correct way to subtract 3.98 from 11.35. What is another correct way?
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In decimal form=-7.37
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Step-by-step explanation:

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The change of the cost changes when the pounds of ham changes. When the pounds of ham is 0, it costs 0 dollars. When the pounds of ham is 3, it costs 12 dollars. The cost changes consistently with the pounds of ham. They change together. Every time the pounds of ham goes up by 3, the cost goes up by 12.

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The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co
Alona [7]

Answer:

95% Confidence interval for the variance:

3.6511\leq \sigma^2\leq 34.5972

95% Confidence interval for the standard deviation:

1.9108\leq \sigma \leq 5.8819

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

s^2=2.89^2=8.3521

The confidence interval for the variance is:

\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128

Then, the confidence interval can be calculated as:

\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819

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