The model (x+a)(x-a) will represents the factors of 4x²-9 as (2x+3)(2x-3).
<h3>What are the quadratic equations in one variable completing the squares method?</h3>
The "completing the squares" method aims to construct a quadratic equation of the form where the x variable is entirely covered by a single squared term, which is the square of a linear expression in x, as the name suggests.
The quadratic equation can resemble this:
x²-a² = (x+a)(x-a)
Given equation;
⇒4x²-9
⇒(2x)²-3²
The equation can be modeled as;
(2x+3)(2x-3)
Hence the model (x+a)(x-b) will represents the factors of 4x²-9 as (2x+3)(2x-3).
To learn more about completing the squares method refer to:
brainly.com/question/16800259
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Answer:
The answer is 8
Step-by-step explanation:
You set the equation 9n=8n+8
Subtract 9n-8n
n=8
Consider this option:
1. if to re-write the condition, it is given: total time t=8 hours; upstream=downstream=6 miles; V_boat=4 m/h., V_current=V=?
2. note, that total time=time_upstream+time_downstream, where time_upstream=6miles/(V_boat-V) and time_downstream=6miles/(V_boat+V). Using this it is possible to make up and solve the following equation:
answer: √10
P.S. the roots of the equation are √10 and (-√10), only positive values is needed for V.
Answer:
The wire is approximately 42feet long
Step-by-step explanation:
We can mentally sketch out the shape that is formed between the guy wire and the antenna tower. This is simply a right-angled triangle with the opposite side being the height of the antenna (30 feet). The adjacent side is the distance on the ground between the point where the wire was fastened and the base of the antenna.
The hypotenuse side is the length of the wire we are looking for.
Parameters are given as:
Opposite : 30ft
Adjacent: 30ft
Hypotenuse: x feet
The hypotenuse = 
Hypotenuse =
