Answer:
Part A none
Part B drawn
Step-by-step explanation:
Suppose the transversal intersects a pair of parallel lines it creates two pairs of alternate exterior angles.
Now if we look at the first figure we find that the alternate exterior angle 1 and 4 are equal . Also 3 and 2 are equal.
But <1 and < 2 are not equal . They are supplementary angles. Their sum is equal to 180 degrees.
Similarly angles 3 and4 are supplementary angles.
This situation does not support Ricky's claim. So you will select none in part A.
Now in part B we see that angle 5 &8 are equal and 6 & 7 are congruent.
This refutes Ricky's claims and this can be proved mathematically.
Angles 5 & 6 are supplementary angles. Similarly 7 & 8 are supplementary therefore they cannot be equal as they are unequal and a transversal is drawn not a perpendicular.
Answer:
I think it's
8 first and then 27/36 then -1/4 and lastly -19/29
Step-by-step explanation:
<h2>I dont know if it's correct</h2>
Answer:
solution given:
B.
CE=2×2=4[base side is double to the line of mid point]
AB=15/2=7.5[b is a mid point]
m<AEC=75°[ corresponding angle]
5.
given:
BD=x+1
CE=x+10
we have
2BD=CE
2(x+1)=x+10
2x+2=x+10
2x-x=10-2
x=8