Answer:
(16,1)
Step-by-step explanation:
Answer:
*In Explanation
Step-by-step explanation:
<u>1) Start by just substituting the value of x (given in equation 1) into the second equation:</u>
y = 3x - 1
y = 3(2) - 1
y = 6-1 = 5
<u>2) Since both equations have x on one side, make both equations equal to one another:</u>
2y + 4 = 9 - 3y
<u>Solve for y:</u>
5y = 5
y = 1
<u>Plug y = 1 into either one of the given equations and solve for x:</u>
I'll use first equation:
x = 2y + 4
x = 2(1) + 4
x = 6
<u>3) When substituting X into the second equation, remember to use parenthesis:</u>
The student was substituting x from equation 1 into equation 2, but they forgot to multiply ALL of 2y + 3 by 2.
x = 2y + 3
Substitute into 2nd eqn:
y = 2(2y + 3) - 9
Answer:
Compound interest = $365.4
Step-by-step explanation:
Given:
Amount borrowed = $6,000
Rate of interest = 3%
Number of year = year
Find:
Compound interest
Computation:
A = P[1+r]ⁿ
Amount after 2 year = 6,000[1 + 3%]²
Amount after 2 year = 6,000[1 + 0.03]²
Amount after 2 year = 6,000[1.03]²
Amount after 2 year = 6,000[1.0609]
Amount after 2 year = 6,365.4
Compound interest = Amount after 2 year - Amount borrowed
Compound interest = 6,365.4 - 6,000
Compound interest = $365.4
