They are able to have the same value as the negative sign is simply transferred to the inside. Either way 4 is being subtracted from 3.
ANSWER
D.
![A=3,P=2\pi,PS=(4,9)](https://tex.z-dn.net/?f=%20A%3D3%2CP%3D2%5Cpi%2CPS%3D%284%2C9%29)
EXPLANATION
The given function is
![f(x) = 3 \sin(x - 4) + 9](https://tex.z-dn.net/?f=f%28x%29%20%3D%203%20%5Csin%28x%20-%204%29%20%2B%209)
Comparing to the general form of a trigonometric sine function,
![f(x) = A \sin(Bx-C)+D](https://tex.z-dn.net/?f=f%28x%29%20%3D%20A%20%5Csin%28Bx-C%29%2BD)
![A=3](https://tex.z-dn.net/?f=A%3D3)
The amplitude is absolute value of A
![|A| = |3| = 3](https://tex.z-dn.net/?f=%20%7CA%7C%20%3D%20%7C3%7C%20%3D%203)
![B=1](https://tex.z-dn.net/?f=B%3D1)
The period is given by
![p = \frac{2\pi}{ B}](https://tex.z-dn.net/?f=p%20%3D%20%5Cfrac%7B2%5Cpi%7D%7B%20B%7D%20)
![p = \frac{2\pi}{ 1} = 2\pi](https://tex.z-dn.net/?f=p%20%3D%20%5Cfrac%7B2%5Cpi%7D%7B%201%7D%20%3D%202%5Cpi)
![C=4](https://tex.z-dn.net/?f=C%3D4)
is a shift to the right of 4 units.
and
![D=9](https://tex.z-dn.net/?f=D%3D9)
is an upward shift of 9 units
Therefore the phase shift is (4,9).
The correct answer is D
Point two should be your answer
Answer: the second column is 12, then 15, then 6
Step-by-step explanation:
that is some good chocolate milk
It these triangles are similar, then the sides of the triangles are in proportion:
<em>cross multiply</em>
<em>use distributive property</em>
<em>subtract 10y from both sides</em>
<em>divide both sides by 5</em>
![\boxed{y=8}](https://tex.z-dn.net/?f=%5Cboxed%7By%3D8%7D)
<em>cross multiply</em>
![8x=(4)(6)](https://tex.z-dn.net/?f=8x%3D%284%29%286%29)
<em>divide both sides by 8</em>
![\boxed{x=3}](https://tex.z-dn.net/?f=%5Cboxed%7Bx%3D3%7D)