Incoming students at a certain law school have an average LSAT score of 163 and a Standard Devation (SD) of 8. Tomorrow, one of
1 answer:
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For this case we have the following equations:
The break even point occur when C = R:
We have then:
Clearing x we have:
Then, substituting in any of the equations we have:
The break even point is:
(4, 176)
Answer:
The break even point is:
(4, 176)
The break even point occur when C = R:
We have then:
Clearing x we have:
Then, substituting in any of the equations we have:
The break even point is:
(4, 176)
Answer:
The break even point is:
(4, 176)
If there is no number in between sets of numbers, it's going to be multiplication.
So (w+2) x (w+7)
w+2, well, evaluates into w+2.
w+7 is w+7.
We'll use the FOIL method for this.
FOIL stands for:
First
Outer
Inner
Last
Let's start with the first terms. Multiply them.
So: w * w.
Combine both w's, and you get
.
Now multiply the outer terms.
w * 7 = 7w.
Then the inner terms. 2 and w.
2 x w = 2w.
So our current numbers are:, 7w, and 2w.
We can add 7w and 2w together.
7w + 2w = 9w.
Now multiply the last terms.
2 x 7 = 14.
So, this simplifies to
Hope this helped!
So (w+2) x (w+7)
w+2, well, evaluates into w+2.
w+7 is w+7.
We'll use the FOIL method for this.
FOIL stands for:
First
Outer
Inner
Last
Let's start with the first terms. Multiply them.
So: w * w.
Combine both w's, and you get
Now multiply the outer terms.
w * 7 = 7w.
Then the inner terms. 2 and w.
2 x w = 2w.
So our current numbers are:
We can add 7w and 2w together.
7w + 2w = 9w.
Now multiply the last terms.
2 x 7 = 14.
So, this simplifies to
Hope this helped!