When substituting, you want to take the y value from one equation and plug it into the y variable in the other equation to find the x value. When you find the c value, you plug the number into one of the equations to get your y value.
<h2>19.</h2><h3>Given</h3>
- window width and height are in proportion to building width and height
- window width and height are 11 in and 18 in, respectively
- building height is 108 ft
<h3>Find</h3>
<h3>Solution</h3>
The proportional relation can be written as
... (building width)/(building height) = (window width)/(window height)
Multiplying by (building height) gives
... (building width) = (building heigh) × (window width)/(window height)
... (building width) = 108 ft × (11 in)/(18 in)
... building width = 66 ft
<h2>21.</h2><h3>Given</h3>
- map distance = 6.75 in
- map scale = 1.5 in : 5 mi
<h3>Find</h3>
<h3>Solution</h3>
The distances are in proportion, so
... (map distance) : (actual distance) = 1.5 in : 5 mi
Multiplying by (5 mi)/(1.5 in)×(actual distance), we have
... (5 mi)/(1.5 in)×(6.75 in) = (actual distance) = 22.5 mi
Answer:
Step-by-step explanation:
Given expression:
![\left[(-4)^5\right]^3](https://tex.z-dn.net/?f=%5Cleft%5B%28-4%29%5E5%5Cright%5D%5E3)
Answer:
14
Step-by-step explanation:
6(2)
12
4÷2
2
12+2
pemdas
