Answer:
1:4:12
Step-by-step explanation:
George = x
Alex = 12 + x
Carl = 3(12 + x) = 36 + 3x
x + 12 + x + 36 + 3x = 68
5x + 48 = 68
5x = 20
x = 4
George = x = 4
Alex = 12 + x = 12 + 4 = 16
Carl = 36 + 3x = 36 + 3(4) = 48
4:16:48 = 1:4:12
The ratio is 1:4:12.
Answer:
23.99
Step-by-step explanation:
Jean Gray's total earnings over the past week was $3,925
Since Jean earns 4% for the first $2,00 business she does, she earns a base commission of = $2,000*0.04 = $80
Now, we need to find how of additional sales did Jean do over and above the base of $2,000. This is calculated as follows:
Total Sales = 3,925
Base sales =2,000
Add-on sales = 3,925-2,000 = 1,925
For the $1,925 sales, Jeans earns 8% commission, her commission for this will be 1,925*0.08 = $154
So, the total commission = $80 + $154 = $234
Her commission for the week was $234
The <span>tree diagram associated with the experiment of selecting two batteries from among four, the defective answer is <span>third one.
</span>Attached with answer is the tree diagram that shows the batteries.
</span>As shown in the image, ofall twelve
possible outcomes, we can see that event N1 contains 9 of these outcomes, and N1N2
contains 6. Thus, because the 12 outcomes are equally likely to be 2/3
Answer:
0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Step-by-step explanation:
We solve this question working with the probabilities as Venn sets.
I am going to say that:
Event A: Taking a math class.
Event B: Taking an English class.
77% of students are taking a math class
This means that 
74% of student are taking an English class
This means that 
70% of students are taking both
This means that 
Find the probability that a randomly selected student is taking a math class or an English class.
This is
, which is given by:

So

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
Find the probability that a randomly selected student is taking neither a math class nor an English class.
This is

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class