Firstly, let's factorise each equation individually - to do this, find 2 numbers that when summed add to the value of the second term, and when multiplied give the value of the third term.
7 and 12 give us 4 and 3 (4+3=7, 4*3=12) -- 8 and 15 give us 5 and 3 (5+3=8, 5*3=15)
Now we can rewrite these equations as (y+4)(y+3) and (y+5)(y+3) respectively.
Putting this in a fraction: (y+4)(y+3)/(y+5)(y+3) -- We can clearly see that there is a y+3 on both sides of the fraction, and given there are no terms outside of the brackets being multiplied, we can directly cancel.
This gives us our final answer:
(y+4)/(y+5)
Answer:1) 32. 2). 3) 21. 4) 4
Step-by-step explanation: 1) 4*8=32m, 2) I don't know, 3) 6*7=42 for the area of a square but since a triangle half it so its 21, An the last is by 4 for example 4*10=40 but if doubled its 20*8 and that equals 160. and 160/40=4
Answer:
.8
Step-by-step explanation:
Answer:
A. Discriminant = 116
B. Number of solutions for the quadratic equation = 2
C. Type of solutions (circle one):Imaginary
D. Type of solutions (circle one):irrational
Step-by-step explanation:
The given quadratic equation is
We rewrite in standard form to get;
The discriminant is
where a=1, b=8, c=-13
We substitute to get:
Since the discriminant is great than zero, we have two distinct real roots
