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Maru [420]
4 years ago
8

Find the slope and y-intercept of the line. y=4/3x-3

Mathematics
1 answer:
icang [17]4 years ago
5 0
Simple....

you have: y= \frac{4}{3} x-3

The slope is m=\frac{4}{3}(x)

The y-intercept is at (0,-3)

Thus, your answer.
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Can someone tell me if I got this question correct please:
DENIUS [597]
It does not exist because the function is not continuous at -2.
Substitute -2 into both rules and they must equal the same number.
USING a TI-83 plus press Y= in Y1 put (2x+5)(x<-2) and in Y2 put (x+4)(x≥-2)
Arrow over in front Y1 and press ENTER until you see only 3 diagonal dots
Do the same in front of Y2.
Inequality signs are under 2nd MATH
Press GRAPH (You can see it is not continuous at -2)
4 0
3 years ago
HELP ASAP!!!!!! Please
MissTica

1. Distributive property, because you are "distributing" the 5 across the parentheses.

2. Since we know that 5/10 is 0.5, this term must be close to that. 5/9 is about 0.55555, therefore, I'd go with 5/9 = 0.55

Hope I could help!

8 0
3 years ago
The sum of the first number cubed and the second number is 500 and the product is a maximum.
soldier1979 [14.2K]

We are given the following information:

the sum of the first number cubed and the second number is 500

their product is a maximum

We are looking for the 2 missing numbers.

To answer this, let's represent the two numbers as x and w.

From the given, we can form the following equation:

x^3+w=500

We can then express y as:

w=500-x^3

We can express their product as:

x(500-x^3)=500x-x^4

To find the maximum value of x, let's solve for the derivative of -x^4 + 500 x.

\begin{gathered} f(x)=-x^4+500x \\ f^{\prime}(x)=-4x^3+500 \end{gathered}

Then we solve for the value of x where f'(x) = 0.

\begin{gathered} -4x^3+500=0 \\ -4x^3=-500 \\ x^3=125 \\ x=5 \end{gathered}

Then we use x = 5 to solve for the second number, w.

\begin{gathered} w=500-x^3 \\ w=500-5^3 \\ w=500-125 \\ w=375 \end{gathered}

Therefore, the two numbers are 5 and 375.

3 0
1 year ago
At a local high school, enrollment in the drama club increases by 5% each year. What is the common ratio in this situation? 0. 0
Crazy boy [7]

The common ratio in the geometric progression is the ratio of any one phrase in the series divided by the preceding term. The common ratio in this situation is 1.05.

<h3>What is the common ratio?</h3>

The common ratio in the geometric progression is the ratio of any one phrase in the series divided by the preceding term. It is usually symbolized by the letter "r."

The given data in the problem will be;

Enrollment in the drama club increases by 5% each year

If the value of old enrollment is x and the value of new enrollment is y then

\rm y=x+5 \% \  of\ x \\\\ y=x+0.05x= 1.05 x

The common ratio in the new and old is found by;

\rm r= \frac{1.05x}{x} \\\\ \rm r= 1.05

Hence C is correct. The common ratio in this situation is 1.05.

To learn more about the common ratio refer to the link;

brainly.com/question/13162487

8 0
3 years ago
Fnd the area of the figure. 13cm 15cm 11cm​
Gekata [30.6K]

Answer:

39

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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