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alexgriva [62]
2 years ago
5

What is the range of this line?

Mathematics
1 answer:
hodyreva [135]2 years ago
5 0
(-infinity, -2)

(i’m not 100% positive, but i think its right)
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marta [7]
Distance between school and Amy's house is 7 units. Now go to the horizontal line on the right. Count up to 7 units there and then go up 3. Plot that and label it Amy's grandmother's house. The distance between Amy and her grandma is 6 units. It is units beause you -don't know if one square is a block or a mile, so you just call it units.
4 0
3 years ago
Read 2 more answers
Find f^-l for f (x) = 1/2•6^x-1
stepladder [879]

Answer:

u may need more like a calculator

Step-by-step explanation:

5 0
3 years ago
The length of the box is 2 1/2 m, it is 1 9/16 times its width. What is the height of the box if its volume is 12 3/4 m3?
skelet666 [1.2K]

Answer:

3\frac{3}{16} meter

Step-by-step explanation:

We have to write first what is known from the information.

Let's say, length is L, width is W, and height is H

1. The length of the box is 2 1/2 m = 2,5 m = 5/2 m, it is 1 9/16 = 25/16 times it's width (L). So we have the equation :

L ≡ \frac{5}{2} = \frac{25}{16} W

Then we find the W. From the fraction above, we found W equals to \frac{8}{5} = 1,6 meter

2. What is the height of the box, if its volume is 12 3/4 m^3 = 51/4 m^3

Formula of a volume is :

The area wide times the height

In this problem, the equation is :

L × W × H = Volume

Insert the numbers,

\frac{5}{2} × \frac{8}{5} × H = \frac{51}{4}

From the fraction above, we can find that H equals to

3\frac{3}{16} meter

3 0
3 years ago
An art museum has a pentagon-shaped room. When drawn to scale on a coordinate grid, the corners of the room are points (18,20):
AURORKA [14]

Answer:

2\ gal

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(18,20),B(4,20),C(4,4),D(16.2),E(22.10)

step 1

Find the distance AB

we have

A(18,20),B(4,20)

substitute in the formula

d=\sqrt{(20-20)^{2}+(4-18)^{2}}

d=\sqrt{(0)^{2}+(-14)^{2}}

AB=14\ ft

step 2

Find the distance BC

we have

B(4,20),C(4,4)

substitute in the formula

d=\sqrt{(4-20)^{2}+(4-4)^{2}}

d=\sqrt{(-16)^{2}+(0)^{2}}

BC=16\ ft

step 3

Find the distance DE

we have

D(16.2),E(22.10)

substitute in the formula

d=\sqrt{(10-2)^{2}+(22-16)^{2}}

d=\sqrt{(8)^{2}+(6)^{2}}

d=\sqrt{100}

DE=10\ ft

step 4

Find the distance AE

we have

A(18,20),E(22.10)

substitute in the formula

d=\sqrt{(10-20)^{2}+(22-18)^{2}}

d=\sqrt{(-10)^{2}+(4)^{2}}

d=\sqrt{116}

AE=10.77\ ft

step 5

Find out the area of the four walls

To determine the area sum the length sides and multiply by the height of the walls

so

A=(AB+BC+DE+AE)h

substitute the given values

The height of the walls is 10 ft

A=(14+16+10+10.77)10

A=(50.77)10

A=507.7\ ft^2

step 6

Determine the number of gallons needed to paint the four walls

we know that

one gallon of paint is enough to cover 400 square feet

using proportion

\frac{1}{400}\ \frac{gal}{ft^2}=\frac{x}{507.7}\ \frac{gal}{ft^2}\\\\x=507.7/400\\\\x= 1.27\ gal

Round up

x=2\ gal

5 0
3 years ago
The sum of four and three multiplied by the quotient of four and two
asambeis [7]

Answer:

14

Step-by-step explanation:

4+3=7

4/2=2

7•2=14

8 0
3 years ago
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