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2 years ago

5

What is the range of this line?

1 answer:

hodyreva [135]2 years ago

5 0

(-infinity, -2)

(i’m not 100% positive, but i think its right)

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Can someone help me

marta [7]

Distance between school and Amy's house is 7 units. Now go to the horizontal line on the right. Count up to 7 units there and then go up 3. Plot that and label it Amy's grandmother's house. The distance between Amy and her grandma is 6 units. It is units beause you -don't know if one square is a block or a mile, so you just call it units.

4 0

3 years ago

Read 2 more answers

Find f^-l for f (x) = 1/2•6^x-1

stepladder [879]

Answer:

u may need more like a calculator

Step-by-step explanation:

5 0

3 years ago

The length of the box is 2 1/2 m, it is 1 9/16 times its width. What is the height of the box if its volume is 12 3/4 m3?

skelet666 [1.2K]

Answer:

$3\frac{3}{16}$ meter

Step-by-step explanation:

We have to write first what is known from the information.

Let's say, length is L, width is W, and height is H

1. The length of the box is 2 1/2 m = 2,5 m = 5/2 m, it is 1 9/16 = 25/16 times it's width (L). So we have the equation :

L ≡ $\frac{5}{2} = \frac{25}{16} W$

Then we find the W. From the fraction above, we found W equals to $\frac{8}{5} = 1,6$ meter

2. What is the height of the box, if its volume is 12 3/4 m^3 = 51/4 m^3

Formula of a volume is :

The area wide times the height

In this problem, the equation is :

L × W × H = Volume

Insert the numbers,

$\frac{5}{2}$ × $\frac{8}{5}$ × H = $\frac{51}{4}$

From the fraction above, we can find that H equals to

$3\frac{3}{16}$ meter

3 0

3 years ago

An art museum has a pentagon-shaped room. When drawn to scale on a coordinate grid, the corners of the room are points (18,20):

AURORKA [14]

Answer:

$2\ gal$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$A(18,20),B(4,20),C(4,4),D(16.2),E(22.10)$

step 1

Find the distance AB

we have

$A(18,20),B(4,20)$

substitute in the formula

$d=\sqrt{(20-20)^{2}+(4-18)^{2}}$

$d=\sqrt{(0)^{2}+(-14)^{2}}$

$AB=14\ ft$

step 2

Find the distance BC

we have

$B(4,20),C(4,4)$

substitute in the formula

$d=\sqrt{(4-20)^{2}+(4-4)^{2}}$

$d=\sqrt{(-16)^{2}+(0)^{2}}$

$BC=16\ ft$

step 3

Find the distance DE

we have

$D(16.2),E(22.10)$

substitute in the formula

$d=\sqrt{(10-2)^{2}+(22-16)^{2}}$

$d=\sqrt{(8)^{2}+(6)^{2}}$

$d=\sqrt{100}$

$DE=10\ ft$

step 4

Find the distance AE

we have

$A(18,20),E(22.10)$

substitute in the formula

$d=\sqrt{(10-20)^{2}+(22-18)^{2}}$

$d=\sqrt{(-10)^{2}+(4)^{2}}$

$d=\sqrt{116}$

$AE=10.77\ ft$

step 5

Find out the area of the four walls

To determine the area sum the length sides and multiply by the height of the walls

so

$A=(AB+BC+DE+AE)h$

substitute the given values

The height of the walls is 10 ft

$A=(14+16+10+10.77)10$

$A=(50.77)10$

$A=507.7\ ft^2$

step 6

Determine the number of gallons needed to paint the four walls

we know that

one gallon of paint is enough to cover 400 square feet

using proportion

$\frac{1}{400}\ \frac{gal}{ft^2}=\frac{x}{507.7}\ \frac{gal}{ft^2}\\\\x=507.7/400\\\\x= 1.27\ gal$

Round up

$x=2\ gal$

5 0

3 years ago

The sum of four and three multiplied by the quotient of four and two

asambeis [7]

Answer:

14

Step-by-step explanation:

4+3=7

4/2=2

7•2=14

8 0

3 years ago