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alexgriva [62]
3 years ago
5

What is the range of this line?

Mathematics
1 answer:
hodyreva [135]3 years ago
5 0
(-infinity, -2)

(i’m not 100% positive, but i think its right)
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Pls someone help I need this urgently done
Bumek [7]

Answer:

p=3 and q=4 the mistake was in calculating 3q-4q-10=6 let's solve first.

Step-by-step explanation:

if p= 2q-5, substitute the p in the equation3q-2p=6 as

3q-2(2q-5)=6

solve the equation in parentheses :

3q-2(2q-5)\\

multiply  -2 \\ by (2q-5)\\ it will equal to:  3q-4q+10

now we want to let all unknown digits alone, so we will take 10 to the other side with a different sign it will be as:

3q-4q=6-10

now we will solve it:

3q-4q=6-10\\q=-4 at this part, the given equation was wrong in the paper.

we don't want the digit to be negative so we will do it like this:

\frac{-q}{-1} =\frac{-4}{-1 } = q=4

now that we found q we will substitute it to find p\\:

p=2q-5\\q=4\\p=2(4)-5\\p=8-5\\p=3

overall the mistake was in calculating q instead of putting 3q-4q=6-10  

he/she put a different sign in front of the digit like :3q-4q-10=6

so when he/she flipped  -10 it became positive and instead of subtracting he/she added it.  

3 0
2 years ago
Solve for t in the scientific formula
svp [43]
First, multiply both sides by 1000.
1000*c = w*t*c

Since c is on both sides, they cancel each other out
1000 = w*t

Divide both sides by w.
1000/w = t
3 0
3 years ago
Read 2 more answers
Find the measure of the sides of angle ABC with vertices A(1,5), B(3,-2), and C(-3,0). Classify the triangle
Charra [1.4K]

Answer:

AB=\sqrt{53},\ BC=\sqrt{40},\ CA=\sqrt{41}\\It\ is\ an\ acute\ triangle

Step-by-step explanation:

The distance between two points (x_1,y_1),\ (x_2,y_2) is given by \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.

Here A(1,5),\ B(3,-2),\ C(-3,0) are the vertices of a triangle.

AB=\sqrt{(-2-5)^2+(3-1)^2}=\sqrt{(-7)^2+(2)^2}=\sqrt{49+4}=\sqrt{53}=7.28\ unit\\\\BC=\sqrt{(0+2)^2+(-3-3)^2}=\sqrt{(2)^2+(-6)^2}=\sqrt{4+36}=\sqrt{40}=6.32\ unit\\\\CA=\sqrt{(5-0)^2+(1+3)^2}=\sqrt{(5)^2+(4)^2}=\sqrt{25+16}=\sqrt{41}=6.40\ unit

Longest side=AB

AB^2=53\\BC^2+CA^2=40+41=81\\\Rightarrow AB^2

Hence this is an acute triangle.

6 0
3 years ago
PLS HELP WILL MARK BRAINLIEST
Kitty [74]

Answer:

3

Step-by-step explanation:

I think its three i dont do alot of this but yea

5 0
3 years ago
Read 2 more answers
PLEASE HELP
devlian [24]

Answer:

I think it is a 160o Angle

Step-by-step explanation:

7 0
3 years ago
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