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alexgriva [62]
2 years ago
5

What is the range of this line?

Mathematics
1 answer:
hodyreva [135]2 years ago
5 0
(-infinity, -2)

(i’m not 100% positive, but i think its right)
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3 years ago
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8 0
3 years ago
Can someone please explain this problem to me idk what I am doing wrong and can you draw the problem for me thanks
Bogdan [553]

Answer:

  you're not doing anything wrong

Step-by-step explanation:

In order for cos⁻¹ to be a function, its range must be restricted to [0, π]. The cosine value that is its argument is cos(-4π/3) = -1/2. You have properly identified cos⁻¹(-1/2) to be 2π/3.

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Cos and cos⁻¹ are conceptually inverse functions. Hence, conceptually, cos⁻¹(cos(x)) = x, regardless of the value of x. The expected answer here may be -4π/3.

As we discussed above, that would be incorrect. Cos⁻¹ cannot produce output values in the range [-π, -2π] unless it is specifically defined to do so. That would be an unusual definition of cos⁻¹. Nothing in the problem statement suggests anything other than the usual definition of cos⁻¹ applies.

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This is a good one to discuss with your teacher.

4 0
3 years ago
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Yuliya22 [10]

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144 is bigger than 90 so its obtuse triangle

5 0
3 years ago
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