ANSWER

EXPLANATION
The given triangle is a right triangle.
It was given that,

and

Using the Pythagoras Theorem, we can determine the value of c.




The ratio is the adjacent over the hypotenuse.

We rationalize to get:

Answer:

Step-by-step explanation:
Given


Required

First, calculate 
We have:

This gives:

Substitute 


Substitute 



Split

This gives

4x - 2y = 10
-2y = -4x + 10
y = 4/2x - 10/2
y = 2x - 5 <==
Y = 2x³, when x = -3
<span>y = 2*(-3)³
</span>
<span>y = 2*-27
</span>
y = -54
The answer is 4) 140.
If we closely examine the pattern of the series, we see that after a number is subtracted by a value, it is multiplied by the same value, and then it moves on to the next natural number.
- 10 - 2 = 8
- 8 × 2 = 16
- 16 - 3 = 13
- 13 × 3 = 39
- 39 - 4 = 35
The next step, according to the pattern, would be to multiply 4.