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natka813 [3]
3 years ago
8

Simplify cube root of 7 / Fifth root of 7

Mathematics
2 answers:
emmainna [20.7K]3 years ago
7 0
7^(1/3) : 7^( 1/5)= 7^(1/3 -1/5)=7^[(5-3)/15]= 7^[2/15]

the answer is D
OverLord2011 [107]3 years ago
7 0

Answer:

Option D. is the answer.

Step-by-step explanation:

we have to simplify the cube root of \frac{\sqrt[3]{7}}{\sqrt[5]{7} }

= \frac{7^{\frac{1}{3}}}{7^{\frac{1}{5} } }

= 7^{\frac{1}{3}-\frac{1}{5}}

= 7^{(\frac{5-3}{15})}

= 7^{\frac{2}{15}}

Therefore, Option D. 7 to the power of 2 over 15 is the answer.

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Step-by-step explanation:

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