The answer is 8 + 2m cubed. hope this helped.
Use the FOIL method: First, Outside, Inside, Last
3x(2x) = 6x²
3x(-4) = -12x
3(2x) = 6x
3(-4) = -12
6x² -12x + 6x-12
Combine like terms
-12x + 6x = -6x
6x² - 6x - 12 is your answer
hope this helps
Answer: (-2, 0) and (0, -2)
Step-by-step explanation:
This system is:
y + x = -2
y = (x + 1)^2 - 3
To solve this we first need to isolate one of the variables in one fo the equations, in the second equation we have already isolated the variable y, so we can just replace it in the first equation:
(x + 1)^2 - 3 + x = -2
Now we can solve this for x.
x^2 + 2*x + 1 - 3 = -2
x^2 + 2*x + 1 -3 + 2 = 0
x^2 + 2*x + 0 = 0
The solutions of this equation are given by the Bhaskara's formula, then the solutions are:

The two solutions are:
x = (-2 - 2)/2 = -2
In this case, we replace this value of x in the first equation and get:
y - 2 = -2
y = -2 + 2 = 4
This solution is x = -2, y = 0, or (-2, 0)
The other solution for x is:
x = (-2 + 2)/2 = 0
If we replace this in the first equation we get:
y + 0 = -2
y = -2
This solution is x = 0, y = -2, or (0, -2)
Y=8.25x+10
10 is the allowance plus the 8.25 times x which is the hours
Answer:
Step-by-step explanation:
Given that Miguel is playing a game
The box contains 4 chips, 2 with number 1, and other two differntly numbered as 3 and 5.
OUt of these 4, 2 chips are drawn
P(drawing same number) = 2C2/4C2 =
Prob (drawing differnt numbers) = 1-1/6 =
Hence prob of winning 2 dollars = 
Prob of losing 1 dollar = 
b) Expected value = sum of prob x amount won
= 
c) Miguel can expect to lose 1/2 dollars for every game he plays
d) If it is to be a fair game expected value =0
i.e. let the amount assigned be s
Then 