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iragen [17]
3 years ago
11

Help plzzzzzzzzzzzz ​

Mathematics
2 answers:
julsineya [31]3 years ago
5 0

Answer:

with what theres nothing

Step-by-step explanation:

Allushta [10]3 years ago
5 0

Answer:

86.64cm^2 (cm squared)

Step-by-step explanation:

So! This is a cube, a 6-sided shape. All the side lengths will be equal, which makes it really easy to calculate the surface area.

Since you calculate surface area by length x width, you do that once and then multiply it by six to find the total surface area.

So it'd be 3.8cm x 3.8cm = 14.44cm

and then 14.44 cm x 6 = 86.64cm^2, or cm squared.

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Write the equation of the line that contains slope of 4 and a coordinate of (3,11)
k0ka [10]

Answer:

y = 4x - 1

Step-by-step explanation:

To write the equation of a line using the slope and a point, use the point slope form y - y_1 = m(x-x_2).

Substitute m = 4 and (3,11).

y - 11 = 4 ( x- 3)

y - 11 = 4x - 12

y = 4x - 1

3 0
3 years ago
How do you write 7/10 as a percentage? ​
Hunter-Best [27]

Answer:

70%

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Write the polynomial as a product.<br> xk-xy-x^2+yk
Kazeer [188]

Answer:

(k-x)(x+y)

Step-by-step explanation:

x×(k-x)+y×(k-x)

=(k-x)(x+y)

3 0
3 years ago
The bacterial strain Acinetobacter has been tested for its adhesion properties, which is believed to follow a normal distributio
pantera1 [17]

Answer:

a) Alternative hypothesis should be one sided. Because Null and Alternative hypotheses are:

H_{0}: μ=2.66 dyne-cm.

H_{a}: μ<2.66 dyne-cm.

b) the hypothesis that mean adhesion is at least 2.66 dyne-cm is true

Step-by-step explanation:

Let μ be the mean adhesion in dyne-cm.

a)

Null and alternative hypotheses are:

H_{0}: μ=2.66 dyne-cm.

H_{a}: μ<2.66 dyne-cm.

b)

First we need to calculate test statistic and then the p-value of it.

test statistic of sample mean can be calculated as follows:

t=\frac{X-M}{\frac{s}{\sqrt{N} } } where

  • X  is the sample mean
  • M is the mean adhesion assumed under null hypothesis (2.66 dyne-cm)
  • s is the standard deviation known  (0.7 dyne-cm_2)
  • N is the sample size(5)

Sample mean is the average of 2.69, 5.76, 2.67, 1.62 and 4.12 dyne-cm, that is \frac{2.69+5.76+2.67+1.62+4.12}{5} ≈ 3.37

using the numbers we get

t=\frac{3.37-2.66}{\frac{0.7}{\sqrt{5} } } ≈ 2.27

The p-value is ≈ 0.043. Taking significance level as 0.05, we can conlude that sample proportion is significantly higher than 2.66 dyne-cm.

Thus, according to the sample the hypothesis that mean adhesion is at least 2.66  dyne-cm is true

3 0
4 years ago
According to the Graffalo the slope line B is ?:
Drupady [299]

Answer:

yes ikr

Step-by-step explanation:

yes ikr

yes ikr

yes ikr

yes ikr

yes ikr

yes ikr

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yes ikr

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6 0
3 years ago
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