A committee of four is chosen at random from a group of 66 women and 55 men. Find the probability that the committee contains at

Question

4 years ago

15

least one man.

1 answer:

Law Incorporation [45] · Answer 1 · 2022-01-08T07:24:00+03:00

Answer: There are 13 C 4 = 715 ways to choose a group of men and women.

So there are 715 - 70 = 645 ways to choose a group with at least one man.

This means the probability is 645/715 = 129/143 = 0.9020979 (so roughly a 90.20979% chance)

Step-by-step explanation: There are 13 C 4 = 715 ways to choose a group of men and women.

So there are 715 - 70 = 645 ways to choose a group with at least one man.

This means the probability is 645/715 = 129/143 = 0.9020979 (so roughly a 90.20979% chance)