All categories

3 years ago

Pls help this is due very soon

Mathematics

2 answers:

loris [4]3 years ago

8 0

Answer:

669.87 cubic cm

Step-by-step explanation:

$d = 16 \: cm \implies \: r = 8 \: cm \\ h = 10 \: cm \\ V_{cone} = \frac{1}{3} \pi {r}^{2} h \\ \hspace{20 pt} = \frac{1}{3} \times 3.14 \times {8}^{2} \times 10 \\ \hspace{20 pt} = \frac{1}{3} \times 3.14 \times 64 \times 10 \\ \hspace{20 pt} = \frac{1}{3} \times 3.14 \times 640 \\ \hspace{20 pt} = \frac{1}{3} \times 2,009.6 \\ \hspace{20 pt} = 669.866667 \\ \huge \red{ \boxed{V_{cone} = 669.87 \: {cm}^{3} }}\\$

Viefleur [7K]3 years ago

7 0

10x16 = 160 cm

160x 3.14 = 502.4 cm

502.4 ≈ 500 cm

You might be interested in

Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o

NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so $\pi = 0.8$ .

(a) What is the probability she gets an A?

There are four problems, so $n = 4$

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find $P(X \geq 3)$

$P(X \geq 3) = P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096$

$P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096$

$P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192$

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so $n = 3$

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find $P(X \geq 2)$

$P(X \geq 3) = P(X = 2) + P(X = 3)$

$P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384$

$P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512$

$P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896$

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

3 0

3 years ago

Counting how many errors are in one chapter of a book is an example of measuring what kind of quality characteristics

AnnZ [28]

Answer: Attributes.

Step-by-step explanation:

An attribute is characterized as a person, position, or thing's quality or characteristic. Individuals in real life and fictional characters have different characteristics. Someone could be called attractive, charming, funny, or intelligent, for instance. Well, in math, an attribute is a characteristic of a math object - it's what this object has. An attribute of the book is the number of errors in a chapter of the book.

8 0

3 years ago

How would you convert #11?

nekit [7.7K]

The prefix 'd' stands for "deci-", which is a multiplier of 1/10. This 1 dL is 1/10 of a liter. Hence

1 L = 10 dL

Multiply this equation by 6.88, and you get

6.88 L = 68.8 dL

6 0

3 years ago

Q6. The diagram shows two similar solids, A and B.

solniwko [45]

Answer:

640cm³

Step-by-step explanation:

Length SF = ×2

Volume SF = ×2³ = ×8

Volume of B = 8 × 80 = 640cm³

6 0

3 years ago

Using the picture below what fourth point in quadrant I would form a parallelogram

sdas [7]

Answer:

(4,2.5)

.................................

3 0

3 years ago