Write an expression that contains at least two terms and is in simplest form.

Dion need 25% more cookies and Cameron they saw the cookies for $.50 each let X represent the number of cookies Cameron made whi

nataly862011 [7]

Answer:

For this case we have the following variable:

x: the number of cookies Cameron made.

Therefore, the number of cookies Deyonne makes is:

(x + 0.25x)(x+0.25x)

Then, the total sales revenue is:

P = 0.5 * (x + (x + 0.25x))P=0.5∗(x+(x+0.25x))

Rewriting we have: P = 0.5 * (2.25x)P=0.5∗(2.25x)

P = 0.5 * (2.25x)P=0.5∗(2.25x)

P = 1.125xP=1.125x

6 0

3 years ago

F(x)=4x-3, g(x)=10-x<br> Work out gf(x)?

Sedbober [7]

Step-by-step explanation:

Given

f(x) = 4x - 3

g(x) = 10 - x

So Now

gf(x) = g( 4x - 3)

= 10 - 4x + 3

= 13 - 4x

Hope it will help :)❤

3 0

3 years ago

Membership in a skiing club is expected to grow by about 8% per month. Currently, there are 530 members in the club. In about ho

Tpy6a [65]

530 x .08 + 42.40

9 months

7 0

3 years ago

Find the missing part. L=8, w=4, h=2. Find the diagonal of (d) of the retangular solid

marusya05 [52]

The diagonal of the rectangular solid is $d=2 \sqrt{21}$

Explanation:

The length of the rectangular solid is $l=8$

The width of the rectangular solid is $w=4$

The height of the rectangular solid is $h=2$

We need to determine the diagonal of the rectangular solid.

The diagonal of the rectangular solid can be determined using the formula,

$d=\sqrt{l^{2}+w^{2}+h^{2}}$

Substituting the values $l=8$ , $w=4$ and $h=2$ , we get,

$d=\sqrt{8^{2}+4^{2}+2^{2}}$

Squaring the terms, we get,

$d=\sqrt{64+16+4}$

Adding the terms, we have,

$d=\sqrt{84}$

Simplifying, we have,

$d=2 \sqrt{21}$

Thus, the diagonal of the rectangular solid is $d=2 \sqrt{21}$

8 0

4 years ago

How do you start this and find the weight of each shape? I do not remember doing this in class.

suter [353]

Let's say make the shapes, some variable name

say

⛁ ⚪ ◽ ▯
a b c d

so.. if take those are the shapes provided

then we can take a look at the first set and we can say that

2a + b + c = 20

a + 4d + b = 19

a + c = 9

3c + d + a = 19

thus $\bf \begin{cases}
2a + b + c = 20\\
a + 4d + b = 19\\
a + c = 9\\
3c + d + a = 19 
\end{cases}\\\\
-----------------------------\\\\
a+c=9\implies \boxed{c}=9-a\qquad thus
\\\\\\
2a+b+\boxed{9-a}=20\implies \underline{b}=11-a\impliedby thus
\\\\\\
a+4d+\underline{11-a}=19\implies d=\cfrac{8}{4}\implies d=2\\\\
-----------------------------\\\\
then\qquad 3\left(\boxed{9-a } \right)+\boxed{2}+a=19\implies 27-3a+2+a=19
\\\\\\
10=2a\implies 5=a$

and surely you can find the other two

4 0

3 years ago