from the graph we can see that the vertex is at h = -2 and k = - 4, we also know that the parabola runs through the point (-1 , 0)
![\stackrel{vertex}{(\stackrel{h}{-2}~~,~~\stackrel{k}{-4})}\qquad y=a[x-(-2)]^2-4\implies \underline{y=a(x+2)^2-4} \\\\\\ \begin{cases} x=-1\\ y=0 \end{cases}\qquad \implies 0=a(-1+2)^2-4\implies 0=a-4\implies 4=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \underline{y=4(x+2)^2-4}~\hfill](https://tex.z-dn.net/?f=%5Cstackrel%7Bvertex%7D%7B%28%5Cstackrel%7Bh%7D%7B-2%7D~~%2C~~%5Cstackrel%7Bk%7D%7B-4%7D%29%7D%5Cqquad%20y%3Da%5Bx-%28-2%29%5D%5E2-4%5Cimplies%20%5Cunderline%7By%3Da%28x%2B2%29%5E2-4%7D%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20x%3D-1%5C%5C%20y%3D0%20%5Cend%7Bcases%7D%5Cqquad%20%5Cimplies%200%3Da%28-1%2B2%29%5E2-4%5Cimplies%200%3Da-4%5Cimplies%204%3Da%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20%5Cunderline%7By%3D4%28x%2B2%29%5E2-4%7D~%5Chfill)
Actual area = 42ft²
The actual area will simply be calculated as:
= 6 × 7
= 42 feet²
The given expression is
And in the second factor, x is common. So on taking x out, we will get
We can expand it by distributing , that is
Combining like terms,
And that's the expanded form ., and the given expression can also be written in that way .
Answer:
x = -3, 6
Step-by-step explanation:
First, add 18 to both sides
x² - 3x - 18 = 0
+ 18 + 18
x² - 3x = 18
Add 9/4 to both sides because that is the square of half of -3
x² - 3x + 9/4 = 18 + 9/4
Multiply both sides by 4 to get rid of the fractions
(x² - 3x + 9/4 = 18 + 9/4)4
4x² - 12x + 9 = 72 + 9 = 81
Factor the left side of the equation
(2x - 3)² = 81
√(2x - 3)² = √81
Because of the square root, this will result in a positive number and a negative number
2x - 3 = 9
2x - 3 = -9
For both equations, add 3 to both sides then divide by 2
2x - 3 = 9
+ 3 +3
2x = 12
2x/2 = 12/2
x = 6
2x - 3 = -9
+ 3 + 3
2x = -6
x = -3
Answer:
Is that the whole Question??
Step-by-step explanation:
