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Yuri [45]
3 years ago
15

Can someone help me out with these equations? 1. (5+ √3)^2 2. (√6-5√3)^2 3. (6+3√2)^2

Mathematics
1 answer:
Aloiza [94]3 years ago
6 0

9514 1404 393

Answer:

  1. 28 +10√3
  2. 81 -30√2
  3. 54 +36√2

Step-by-step explanation:

It is useful to remember the form for the square of a binomial.

  (a +b)² = a² +2ab +b²

  (a -b)² = a² -2ab +b²

__

1. (5 +√3)² = 5² +2·5·√3 +(√3)² = 25 +10√3 +3

  = 28 +10√3

__

2. (√6 -5√3)² = (√6)² -2·√6·5√3 +(5√3)² = 6 -30√2 +75

  = 81 -30√2

__

3. (6 +3√2)² = 6² +2·6·3√2 +(3√2)² = 36 +36√2 +18

  = 54 +36√2

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<u>Number of terms = 48</u>

<u>common difference = 1.5</u>

This question involves the concept of Arithmetic Progression.

  • The formula for sum of an arithmetic progression series with first and last term given is;

S_{n} = \frac{n}{2}(a + l)

where;

a = first term

l = last term

n = number of terms

  • From the given sequence, we see that;

first term; a = 4

last term; l = 76

Sum of A.P; S_{n} = 1920

  • Plugging in relevant values into the sum of an AP formula, we have;

1920 = \frac{n}{2}(4 + 76)

simplifying this gives;

1920 = 40n

n = 1920/40

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  • Formula for nth term of an AP is;

t_{n} = a_{1} + (n - 1)d

where;

a_{1} is first term

d is common difference

n is number of term

t_{n} is the nth term in question

the 48th term is 76

Thus;

76 = 4 + (48 - 1)d

76 - 4 = 47d

72 = 47d

d = 72/47

d ≈ 1.5

Thus;

Number of terms = 48

common difference = 1.5

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