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coldgirl [10]
3 years ago
13

From greatest to least?? 1.11,0.111,1.01,1.001

Mathematics
2 answers:
vodomira [7]3 years ago
7 0
0.111, 1.001, 1.001, 1.11

hope this helps
ivolga24 [154]3 years ago
6 0

Answer: Here our numbers are 1.11, 0.111, 1.01 and 1.001, we want to order them from more to least.

we need to find the biggest number first, let's take 1.11 first, if the difference between this number and all the others is positive, means that 1.11 is bigger than the other numbers.

then:

1.110 - 0.111= 0.999

1.11 - 1.01 = 0.1

1.11 - 1.001 = 0.109

so 1.11 is the biggest number on our set.

The next number is 1.01 (i choose this because i know that is biggest to 0.111, and also i know is bigger than 1.001 because the 1 after the decimal point is closest to the point)

Lets see the differences to be sure:

1.010 - 0.111 = 0.899

1.010 - 1.001 = 0.009

So 1.01 is bigger than the other two numbers.

Now we need the third, and is easy to see that 1.001 is bigger than 0.111.

then the order is: 1.11 , 1.01 . 1.001 . 0.111

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3 years ago
Nina and Jo both ran an 8 km race. Nina took 55 minutes to run the whole race. Jo started the race 3 minutes later than Nina but
grin007 [14]

Answer:

Step-by-step explanation:

First we figure out how fast Nina can run. If Nina can run 8 km in 55 minutes, then her rate is

\frac{8km}{55min}=.145\frac{km}{min} and we can use that in a d = rt table:

                 d        =        r        *        t

Nina                            .145

Jo

Now we can fill in the distance which is 6 for both, since that is the distance where they met:

                d        =        r       *        t

Nina         6        =     .145

Jo             6        =

Now we go to the info given about the time. If Jo started the race 3 minutes after Nina, that means that Nina is running 3 minutes longer than Jo. Filling in the time info:

                d        =        r        *        t

Nina          6       =       .145    *      t + 3

Jo              6       =         r       *         t

As you can see, right now we have 2 unknowns in Jo's row. But we don't have to! We will go to Nina's row where the only unknown is time and solve for t. If d = rt, then

6 = .145(t + 3) and

6 = .145t + .435 and

5.55 = .145t so

t = 38.379 minutes. This means that Jo was running 38.379 minutes when she caught up to Nina (it took Nina 3 minutes longer than that to go 6 km since she was already running for 3 minutes when Jo started the race). If Jo's time is 38.379, we can use that in her row for t and solve for r. If d = rt, then

6 = r(38.379) and

r = .16 km/min

Let's check it without the rounding (rounding takes away from the accuracy). If 6 = .145(t + 3) and Nina's rate not rounded is .145454545 and t = 38.37931034, then, rewriting without rounding:

6 should equal .145454545( 38.37931034 + 3)

6 ?=? .145454545(41.37931034)

6 ?=? 6.0 so

Jo's rate is .16 km/min rounded

6 0
2 years ago
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