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3 years ago

What is 4x^2+x-1=0 rounded to the nearest hundredth

Mathematics

1 answer:

Anit [1.1K]3 years ago

6 0

Answer:

= −1 ± 17 √8

Step-by-step explanation:

i think, im sorry if this doesn't help...

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2(a + b)= Helppp meee pleaseeeeee

wolverine [178]

Answer:

ITS C

Step-by-step explanation:

MULTIPLIED BY THE NUMBER TO THE LEFT LOL

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3 years ago

Which equation represents the line that has a slope of 1/2 and

scoray [572]

Answer:

Solution given:

slope(m)=½

passing through point (x',y')=(0,3)

now

equation of a line is:

y-y'=m(x-x')

y-3=½(x-0)

y=½x+3

D.y=½x+3 is a required equation of a line.

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3 years ago

What is the correct answer?

mart [117]

There are 8 marks on the line and the first line is 3 long while the second is 2 long
c. 3/8+2/8=5/8

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3 years ago

$20000 is invested in an account that earned 6% p.A. Compounding yearly for 3 years. The interest rate then went up to 8% p.A. F

GuDViN [60]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for the first 3 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$20000\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{per annum, thus once} \end{array}\dotfill &1\\ t=years\dotfill &3 \end{cases}$

$\bf A=20000\left(1+\frac{0.06}{1}\right)^{1\cdot 3}\implies A=20000(1.06)^3\implies \boxed{A=2382.032} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~ \textit{Compound Interest Earned Amount \underline{for the next 4 years}}$

$\bf A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$2382.032\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{per annum, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}$

$\bf A=2382.032\left(1+\frac{0.08}{1}\right)^{1\cdot 4}\implies A=2382.032(1.08)^4\implies \boxed{A\approx 3240.73} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{amount for this period}}{2382.032+3240.73}\implies 5622.762$

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4 years ago

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Sati [7]

Answer:

the answer is C

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers