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3 years ago

15

The equation for line j can be written as y=2x + 8. Another like k is perpendicular to line j and passes through the point (6,-6

). Choose the equation for like k
A. Y= 1/2x-3
B. Y= -1/2x-3
C. Y=-2x-3
D. Y=-3/2x + 3

1 answer:

Semmy [17]3 years ago

7 0

Answer:

B

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 2x + 8 ← is in slope- intercept form

with slope m = 2

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{2}$ , thus

y = - $\frac{1}{2}$ x + c ← is the partial equation

To find c substitute (6, - 6) into the partial equation

- 6 = - 3 + c ⇒ c = - 6 + 3 = - 3

y = - $\frac{1}{2}$ x - 3 ← equation of line k

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