How do you complete a square

1 answer:

7 0

Step 1 Divide all terms by a (the coefficient of x2).
Step 2 Move the number term (c/a) to the right side of the equation.
Step 3 Complete the square on the left side of the equation and balance this by adding the same value to the right side of the equation.

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In the standard Normal distribution, which z-score represents the 99th percentile?

nydimaria [60]

The Z- score representing the 99th percentile is given by 2.33

Problems of commonly distributed samples can be solved using the z-score formula.

For a set with a standard deviation, the z-score scale X is provided by:

Z = ( x- mean )/ standard deviation

Z-score measures how many standard deviations are derived from the description. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the scale is less than X, that is, the X percentage. Subtract 1 with p-value, we get the chance that the average value is greater than X.

To Find the z-result corresponding to P99, 99 percent of the normal distribution curve.

This is the Z value where X has a p-value of 0.99. This is between 2.32 and 2.33, so the answer is Z = 2.33

For more information regarding normal distribution, visit brainly.com/question/12691636

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3 0

2 years ago

A rectangular garden has length and width as given by the expressions below.

Tom [10]

Answer:

P = -12xy - 56y - 42x + 8

Step-by-step explanation:

P = 2L + 2W

P = 2(4 - 7(3x + 4y)) + 2(3x(-2y))

P = 8 - 14(3x + 4y) + 6x(-2y)

P = 8 - 42x - 56y - 12xy

P = -12xy - 56y - 42x + 8

3 0

3 years ago

Read 2 more answers

I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu

ra1l [238]

The imaginary unit $i$ belongs to the set of complex numbers, denoted by $\mathbb C$ . These numbers take the form $a+bi$ , where $a,b$ are any real numbers.

The set of real numbers, $\mathbb R$ , is a subset of $\mathbb C$ , where each number in $\mathbb R$ can be obtained by taking $b=0$ and letting $a$ be any real number.

But any number in $\mathbb C$ with non-zero imaginary part is not a real number. This includes $i$ .

"is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because $2=2+0i$ .

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising $i$ to the $i$ -th power. Since $i=e^{i\pi/2}$ , we have