Answer:
The radius is 5 in
Step-by-step explanation:
The area of a circle is given by the formula
A = pi *r^2
We know the area = 78.5 in^2 (volume would be in^3 area is in^2)
78.5 = 3.14*r^2
Divide each side by 3.14
78.5/3.14 = 3.14/3.14*r^2
25 = r^2
Take the square root of each side
sqrt(25) sqrt(r^2)
5 =r
Answer:
The given matrix is telling us that we must translate the figure one unit to the right side and one unit downside because the first row states 0 x-units and -1 y-units, the second row states 1 x-unit and 0 y-units.
The transformation of the coordinates would be
(1,-1) to (2, -2)
(2,1) to (3, 0)
(4,1) to (5, 0)
(4,-1) to (5, -2)
The image attached shows the representation of the image.
Answer:
m= -3/2
Step-by-step explanation:
First, we must find the slope of the line given. We are given the equation:
y-2/3x=2
We must get this equation in slope-intercept form: y=mx+b (where m is the slope and b is the y-intercept). In order to do this, we must get y isolated.
2/3x is being subtracted from y. We want to preform the inverse, so we should add 2/3x to both sides.
y-2/3x+2/3x=2+2/3x
y=2+2/3x
Rearrange the terms.
y= 2/3x+2
Now the equation is in slope intercept form. (y=mx+b). 2/3 and x are being multiplied, so we know that the slope is 2/3.
Now, we have to find the perpendicular slope. Perpendicular lines have negative reciprocal slopes.
1. Negative
m=2/3
Negate the slope.
m= -2/3
2. Reciprocal
m= -2/3
Flip the numerator (top number) and denominator (bottom number).
m= -3/2
The perpendicular slope is -3/2
B) 7/10
It is B because there are 7 out of 10 possibilities that you would get a number greater than 7 or an odd number.
First you want to figure out what exactly it is you are looking for. We are looking for "capital letters that have rotational symmetry but do not have line symmetry"
So:
1. Must have rotational symmetry.
This means that if we rotate the capital letter 180 deg, either clockwise or counterclockwise, it will still look the same
2. Must not have line symmetry.
If an object has line symmetry, it means that if you draw a line down the middle (in any way), it will be symmetrical on both sides. We need capital letters that do not fit that condition.
Now we look at all capital letters.
We find that H, I, N,O, S, X, and Z are all rotationally symmetrical. Think about it. If you rotate them, they still look the same.
But, we have to make sure they do not have line symmetry. If we draw a line right down the middle of H, I, O and X (**note, the have multiple lines of symmetry), they are symmetrical on both sides of the line.
Now we are left with N, S, and Z
