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USPshnik [31]
3 years ago
10

In the equation, 1/4n+5=51/2 what is n equal to?

Mathematics
2 answers:
Westkost [7]3 years ago
6 0

Answer:

n = 82

Step-by-step explanation:

<h2>Welcome to Brainly!</h2>

So what you have to do here is simplify the fraction 51/2 into a whole number with a decimal. 51/2 will be 25.5 in number form, so you can plug that in:

1/4n + 5 = 25.5

Then subtract 5 from both sides to get n's number by itself:

1/4n = 20.5

At this point, you would multiply the denominator of 1/4 to both sides, which would be 4. So do that now and you will see that:

n = 82

BlackZzzverrR [31]3 years ago
5 0

Answer:

N = 2

Step-by-step explanation:

5 1/2 - 5

= 1/2

1/2 divided by 1/4 = 2

N = 2

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Evaluate the limit with either L'Hôpital's rule or previously learned methods.lim Sin(x)- Tan(x)/ x^3x → 0
Vsevolod [243]

Answer:

\dfrac{-1}{6}

Step-by-step explanation:

Given the limit of a function expressed as \lim_{ x\to \ 0} \dfrac{sin(x)-tan(x)}{x^3}, to evaluate the following steps must be carried out.

Step 1: substitute x = 0 into the function

= \dfrac{sin(0)-tan(0)}{0^3}\\= \frac{0}{0} (indeterminate)

Step 2: Apply  L'Hôpital's rule, by differentiating the numerator and denominator of the function

= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ sin(x)-tan(x)]}{\frac{d}{dx} (x^3)}\\= \lim_{ x\to \ 0} \dfrac{cos(x)-sec^2(x)}{3x^2}\\

Step 3: substitute x = 0 into the resulting function

= \dfrac{cos(0)-sec^2(0)}{3(0)^2}\\= \frac{1-1}{0}\\= \frac{0}{0} (ind)

Step 4: Apply  L'Hôpital's rule, by differentiating the numerator and denominator of the resulting function in step 2

= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ cos(x)-sec^2(x)]}{\frac{d}{dx} (3x^2)}\\= \lim_{ x\to \ 0} \dfrac{-sin(x)-2sec^2(x)tan(x)}{6x}\\

=  \dfrac{-sin(0)-2sec^2(0)tan(0)}{6(0)}\\= \frac{0}{0} (ind)

Step 6: Apply  L'Hôpital's rule, by differentiating the numerator and denominator of the resulting function in step 4

= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ -sin(x)-2sec^2(x)tan(x)]}{\frac{d}{dx} (6x)}\\= \lim_{ x\to \ 0} \dfrac{[ -cos(x)-2(sec^2(x)sec^2(x)+2sec^2(x)tan(x)tan(x)]}{6}\\\\= \lim_{ x\to \ 0} \dfrac{[ -cos(x)-2(sec^4(x)+2sec^2(x)tan^2(x)]}{6}\\

Step 7: substitute x = 0 into the resulting function in step 6

=  \dfrac{[ -cos(0)-2(sec^4(0)+2sec^2(0)tan^2(0)]}{6}\\\\= \dfrac{-1-2(0)}{6} \\= \dfrac{-1}{6}

<em>Hence the limit of the function </em>\lim_{ x\to \ 0} \dfrac{sin(x)-tan(x)}{x^3} \  is \ \dfrac{-1}{6}.

3 0
3 years ago
A hardware store receives a shipment of bolts that are supposed to be 12 cm long. The mean is indeed 12 cm, and the standard dev
Yuliya22 [10]

Answer: 0.9104

Step-by-step explanation:

Given : A hardware store receives a shipment of bolts that are supposed to be 12 cm long.

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Standard deviation : \sigma= 0.2\text{ cm}

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Since, they will declare the shipment defective and return it to the manufacturer if the average length of the 100 bolts is less than 11.97 cm or greater than 12.04 cm.

So for the shipment to be satisfactory, the length of the bolts must be between 11.97 cm and 12.04 cm.

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z=\dfrac{11.97-12}{\dfrac{0.2}{\sqrt{100}}}=-1.5

For x = 12.04

z=\dfrac{12.04-12}{\dfrac{0.2}{\sqrt{100}}}=2

By using the standard normal distribution table ,  the probability that the shipment is found satisfactory will be :-

P(511.97

Hence,  the probability that the shipment is found satisfactory=0.9104

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3 years ago
javon is helping his dad build a tree house. he has a piece of trim that is 13 ft long. how many pieces can Javon cut that are 1
wel
Well a yard is 3 ft
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