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maw [93]
3 years ago
15

The average age three people running for election is 42. A fourth person joins the race and the average drops to 40. What is the

fourth person's age?
Mathematics
1 answer:
bogdanovich [222]3 years ago
5 0

Let a_1,\ldots,a_4 denote the ages of the 4 candidates. Then

\dfrac{a_1+a_2+a_3+a_4}4=40

a_1+a_2+a_3+a_4=160

\dfrac{a_1+a_2+a_3}3+\dfrac{a_4}3=\dfrac{160}3

The average age of the first 3 candidates is 42, so

\dfrac{a_4}3=\dfrac{160}3-42

\implies\boxed{a_4=160-3\cdot42=34}

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Whats the answer for 6b+7-2b=1+5b
Alecsey [184]

Solution,6b+7-2b=1+5b\quad :\quad b=6

Steps:

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\mathrm{The\:Correct\:Answer\:is\:b=6}

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Read 2 more answers
1. Find the digit that makes 3,71_ divisible by 9.
KiRa [710]

<u>QUESTION 1</u>

We want to find the digit that should fill the  blank space to make




3,71-




divisible by 9.




If a number is divisible by 9 then the sum of the digits should be a multiple of 9.





The sum of the given digits is,




3 + 7 + 1 = 11




Since


11 + 7 = 18


which is a multiple of 9.





This means that


3,717


is divisible by 9.



The correct answer is B



<u>QUESTION 2</u>



The factors of the number 30 are all the numbers that divides 30 exactly without a remainder.





These numbers are ;



1,2,3,5,6,10,15,30




The correct answer is A.




<u>QUESTION 3.</u>

We want to find the prime factorization of the number 168.



The prime numbers that are factors of 168 are



2,3 \: and \: 7




We can write 168 as the product of these three prime numbers to obtain,



168={2}^{3}\times 3\times7





We can also use the factor tree as shown in the attachment to write the prime factorization of 168 as



168 ={2}^{3}\times 3\times7




The correct answer is B.





QUESTION 4.



We want to find the greatest common factor of


140\:\:and\:\:180



We need to express each of these numbers as a product of prime factors.



The prime factorization of 140 is




140={2}^{2}\times 5\times7.



The prime factorization of 180 is



180={2}^{2} \times{3}^{2}\times5.




The greatest common factor is the product of the least degree of each common factor.




GCF={2}^{2}\times5




GCF=20


The correct answer is A.




QUESTION 5.



We want to find the greatest common factor of


15,30\: and\:60.



We need to first find the prime factorization of each number.




The prime factorization of 15 is



15=3\times5.



The prime factorization of 30 is


30=2\times 3\times 5.



The prime factorization of 60 is




60={2}^{2}\times3 \times5





The greatest common factor of these three numbers is the product of the factors with the least degree that is common to them.





GCF=3 \times5





GCF=15



The correct answer is C.




QUESTION 6



We want to determine which of the given fractions is equivalent to


\frac{3}{8}.



We must therefore simplify each option,





A.\: \: \frac{15}{32}=\frac{15}{32}





B.\:\:\frac{12}{32}=\frac{4\times 3}{4\times8}=\frac{3}{8}




C.\:\:\:\:\frac{12}{24}=\frac{12\times1}{12\times 2}=\frac{1}{2}






D.\:\:\frac{9}{32}=\frac{9}{32}




The simplification shows that


\frac{12}{32}\equiv \frac{3}{8}




The correct answer is  B.






QUESTION 7.




We want to express


\frac{10}{22}


in the simplest form.




We just have to cancel out common factors as follows.




\frac{10}{22}=\frac{2\times5}{2 \times11}



This simplifies to,



\frac{10}{22}=\frac{5}{11}




The correct answer is C.






QUESTION 8.




We were given that Justin visited 25 of the50 states.

The question requires that we express 25 as a fraction of 50.




This will give us


\frac{25}{50}=\frac{25\times1}{25\times2}



We must cancel out the common factors to have our fraction in the simplest form.




\frac{25}{50}=\frac{1}{2}




The correct answer is C.





QUESTION 9.





We want to write


2\frac{5}{8}


as an improper fraction.




We need to multiply the 2 by the denominator which is 8 and add the product to 5 and then express the result over 8.




This gives us,



2 \frac{5}{8}=\frac{2\times8+5}{8}



this implies that,


2\frac{5}{8}=\frac{16+5}{8}





2\frac{5}{8}=\frac{21}{8}




Sarah needed


\frac{21}{8}\:\:yards




The correct answer is D.




QUESTION 10




See attachment






QUESTION 11



We wan to write


3\: and\:\:\frac{7}{8}



as an improper fraction.




This implies that,



3+\frac{7}{8}=3\frac{7}{8}





To write this as a mixed number, we have,




3\frac{7}{8}=\frac{3\times8+7}{8}





This implies that,



3\frac{7}{8}=\frac{24+7}{8}





This gives



3\frac{7}{8}=\frac{31}{8}




The correct answer is B.


QUESTION 12


We want to find the LCM of 30 and 46 using prime factorization.


The prime factorization of 30 is 30=2\times 3\times 5


The prime factorization of 46 is 40=2\times 23.


The LCM is the product of the common factors with the highest degrees. This gives us,



LCM=2\times \times3 5\times 23


LCM=690


The correct answer is D.


QUESTION 13

We want to find the least common multiple of 3,6 and 7.


The prime factorization of 3 is 3.


The prime factorization of 6 is 6=2\times 3.


The prime factorization of 7 is 7.


The LCM is the product of the common factors with the highest degrees. This gives us,

LCM=2\times3 \times7


LCM=42.


The LCM is 42, therefore 42 days will pass before all three bikes will at the park on the same day again.


The correct answer is B.


See attachment for continuation.






6 0
3 years ago
Read 2 more answers
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