Answer:
H0: μ = 5 versus Ha: μ < 5.
Step-by-step explanation:
Given:
μ = true average radioactivity level(picocuries per liter)
5 pCi/L = dividing line between safe and unsafe water
The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.
A type I error, is an error where the null hypothesis, H0 is rejected when it is true.
We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.
Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.
(2/7)^2 x (7/9)^2
((2^2)/(7^2)) x ((7^2)/(9^2))
(4/49) x (49/81)
*Cross multiply*
(4/81)
Answer:
A. 2CO + O2 ---> 2CO2
Step-by-step explanation:
2CO + O2 ---> 2CO2
Answer:
Step-by-step explanation:
I haven't got time to do all these by I'll give you the method in each case.
You have to make the x or y term equal (or 1 term + and other -) in both equations before adding or subtracting.
A . Multiply equation 2 by 2 and subtract (to eliminate x)
- don't forget to multiply EACH TERM by 2.
B. Multiply equation 2 by -2 and add.
C. Multiply equation 1 by 3 and equation 2 by 2 ( this will give -6y and +6y in the resulting equations ) so you then add to eliminate y.
D. Multiply equation 1 by 13 and equation and equation 2 by 2 to eliminate x then add.
