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3 years ago

14

Solve Equation log (x-9) = 1 - log x

1 answer:

Licemer1 [7]3 years ago

6 0

$\log (x-9) = 1 - \log x \\
D:x-9>0 \wedge x>0\\
D: x>9 \wedge x>0\\
D:x>9\\
\log(x-9)+\log x=1\\
\log x(x-9)=1\\
10^1=x^2-9x\\
x^2-9x-10=0\\
x^2+x-10x-10=0\\
x(x+1)-10(x+1)=0\\
(x-10)(x+1)=0\\
x=10 \vee x=-1\\
-1\not \in D \Rightarrow x=10
$

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So, Haley uses 2.25 cup of sugar foe each pie.

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