There are .3 decimeters in 3 centimeters
The answer would be D just took test
A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9
B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6
C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16
D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25
The answer is D.
Answer:
Step 2:
Part A
f(x) = a(x-h)^2 +k
Part B
I'm not really sure about this part
Part C
f(x)=-12/25(x-25)^2+32
Step 3:
Part A
y = ax^2 + bx + c
Part B
f(x) = -12/25(x - 25)^2 + 32
Part C
a = -12/25
b = 0
c = 32
Step-by-step explanation:
Hope This Helps!
Sorry For Taking So Long!
