What is the relationship between the number 6 in the number536 and the number 6 in the number 563

zzz [600]

Answer:

G. $\frac{3.2}{2} = \frac{a}{8}$

Step-by-step explanation:

Given that figure I and figure II are similar, it follows that the ratio of their corresponding side lengths are equal and the same.

Thus:

$\frac{3.2}{2} = \frac{a}{8} = \frac{8}{5} = \frac{6.4}{b}$

Therefore, the proportion that must be true is:

✔️ $\frac{3.2}{2} = \frac{a}{8}$

3 0

3 years ago

Find the equation of a line parallel to y - 5x = 10 that passes through the point (3, 10). (answer in slope-intercept form)

Maru [420]

I think it would be the second one

8 0

3 years ago

Read 2 more answers

3x - y = 2<br> 3x - y = 3

expeople1 [14]

Answer:

there is no answer ( I mean this system of equations can't be solved)

Step-by-step explanation:

Because the x eliminates itself there will be no point.

6 0

3 years ago

Jennys room is 13 feet long and 12 feet wide, Ruth's room is 14 feet long and 11 feet wide, whose room has the greater area?

meriva

Answer:

Jenny's room

Step-by-step explanation:

13x12 = 156 and 14x11 = 154

Therefore Jenny's room is bigger.

6 0

3 years ago

Calculus piecewise function.

Kipish [7]

Part A

The notation $\lim_{x \to 2^{+}}f(x)$ means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows $\lim_{x \to 2^{+}}f(x) = 2$

Then for the left hand limit $\lim_{x \to 2^{-}}f(x)$ , we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, $\lim_{x \to 2^{-}}f(x) = 1$

===============================================================

Part B

Because $\lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x)$ this means that the limit $\lim_{x \to 2}f(x)$ does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since $\lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3$ , this means the limit $\lim_{x \to 4}f(x)$ does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0

1 year ago